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3 years ago

A grading machine can grade 48 tests in 1 minute. How

1 answer:

3 0

$\bf \begin{array}{ccll}
tests&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
48&1\\
300&m
\end{array}\implies \cfrac{48}{300}=\cfrac{1}{m}\implies m=\cfrac{300\cdot 1}{48}$

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HELP QUICK PLEASE!! WILL GIVE BRAINLIEST ANSWER

Alex

F(12)=-34(12)+2
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f(12)=-406

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3 years ago

Is (x - 1) a factor of P(x) = 4x? - 9x2 + 4x+1? If it is, write P(x) as a product of

trasher [3.6K]

Answer: i don't even know what a factor is

Step-by-step explanation:

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3 years ago

Rachel rides her bike due east at 9 miles per hour. Amos rides his bicycle due north at 12 miles per hour. If they left from the

Svetach [21]

They will be 15 miles apart after one hour if they left the same point at the same time.

<h3>How do we measure and calculate the distance in Geometry?</h3>

The distance between two points in geometry can be calculated by using the Pythagoras theorem.

Mathematically, the Pythagoras theorem can be expressed as:

$\mathbf{d = \sqrt{x^2 +y^2}}$

where;

x and y are opposite and adjacent sides respectively.

$\mathbf{d = \sqrt{(9)^2 +(12)^2}}$

$\mathbf{d = \sqrt{81+144}}$

$\mathbf{d = \sqrt{225}}$

d = 15 miles

Therefore, we can conclude that they will be 15 miles apart after one hour if they left the same point at the same time.

Learn more about calculating the distance between two points here:

brainly.com/question/7243416

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2 years ago

Solve log x = 2.<br><br> 100<br><br> 1,000<br><br> 2<br><br> 20

dybincka [34]

keeping in mind that when the logarithm base is omitted, the base 10 is assumed.

$\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x$

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2 years ago

Which of the following are like terms?

SVETLANKA909090 [29]

Answer: D) 13y^25 and 2y^25

Like terms involve the same variables, and each of those variables must have the same exponents.

Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.

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3 years ago