All categories

3 years ago

23,569 pennies rounded to nearest ten thousands

Mathematics

2 answers:

satela [25.4K]3 years ago

7 0

Answer:

Nearest ten thousands 20000,

Step-by-step explanation:

Given :23,569

To find : Rounded to the nearest ten thousands

Solution: We have given that 23,569

We can write it as 23,569

Step 1 : Identify the ten thousands digit 2 in 23,569

Step 2: Identify the next smallest place value 3 in 23,569

Step 2: We can the digit less than five, so it would be rounded down

Step 3 : The ten thousands remain same and Every digit after becomes a zero.

Step 4 : Number become 20000.

Therefore, nearest ten thousands 20000,

8_murik_8 [283]3 years ago

4 0

since the thousands place is a 3 which is lower than a 5

it would be rounded to 20,000

You might be interested in

*please help asap!!! will mark brainliest!*

shutvik [7]

Answer:

Step-by-step explanation:

The number would be:

= 2 + (-6 + 20)

= 2 - 6 + 20 = 16

Hope this right because your question is not very clear! :3

5 0

3 years ago

Use multiplication to find 2 equivalent fraction for 3/4 and 4/5

Contact [7]

Equivalent fractions for 3/4 are 6/8 and 9/12

Equivalent fractions for 4/5 is 8/10 and 12/15

7 0

3 years ago

2. A company's manager estimated that the cost C, in dollars, of producing n items is = 7n + 350. The company

Vanyuwa [196]

Answer:

Step-by-step explanation:

the answer is d because you have to multiply the 7 x 12 than do n>84 which is your answer because you cant do anything with it.

4 0

4 years ago

What is the solution of the inequality |2x+3|≤7?

Allushta [10]

Assuming you want to solve for x the result can vary. The result can be shown in multiple forms. Hope this helps!

Inequality Form:
−5≤x≤2
Interval Notation:
[−5,2]

6 0

3 years ago

Find the value of sin(a/2) if cosa= 12/13<br>

daser333 [38]

Answer: sin $\frac{a}{2}$ = ± $\frac{1}{\sqrt{26} }$

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ± $\sqrt{(1-} \frac{cos2A}{2} )$

As required, set A = $\frac{a}{2}$ & cos a= $\frac{12}{13}$ ,thus we get

sin $\frac{a}{2}$ =± $\sqrt{\frac{1-cos a}{2} }$

∴ sin $\frac{a}{2}$ =± $\sqrt{\frac{1-\frac{12}{13} }{2} }$ = ± $\frac{1}{\sqrt{26} }$

since ,360° < $\frac{a}{2}$ <450°

,180° < $\frac{a}{2}$ <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

5 0

3 years ago