You first divide both numbers by 4 to get one quarter which is the unit, and to get the rate, you divide 15 by 4 also. i got the unit rate is 3.75 points oer quarter.

3 0

3 years ago

1.Find the compound interest on Rs25000 for 3 years at 10% per annum ,Compounded annually.

LekaFEV [45]

Answer:

The compound interest is Rs8275

Step-by-step explanation:

The rule of the compound interest is A = P $(1+\frac{r}{n})^{nr}$ , where

A is the new amount

P is the initial amount

r is the interest rate in decimal

n is the number of periods

t is the time

The interest I = A - P

∵ The amount of investment is Rs25000 for 3 years

∴ P = 25000

∴ t = 3

∵ The rate of interest is 10% per annum, compounded annually

∴ r = 10% = 10 ÷ 100 = 0.1

∴ n = 1 ⇒ compounded annually

→ Substitute these value in the 1st rule above to find the new amount

∵ A = 25000 $(1+\frac{0.1}{1})^{1(3)}$

∴ A = 25000 $(1.1)^{3}$

∴ A = Rs33275

→ Use the 2nd rule above to find the interest

∵ I = 33275 - 25000

∴ I = 8275

∴ The compound interest is Rs8275

6 0

2 years ago

Someone please help.

Alexxandr [17]

Hi there!

$f(x)+f(x+1)=4f(x)$

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

1) f(x)

We're given that $f(x)=3^x$ :

⇒ $f(x)=3^x$ :

2) f(x+1)

Now, we must find f(x+1). To do so, add 1 to x in the original function $f(x)=3^x$ :

⇒ $f(x+1)=3^x^+^1$

3) 4f(x)

To find 4f(x), multiply the original function $f(x)=3^x$ by 4:

$4f(x)=4*3^x$ :

4) Put it all together

Now, plug each of the three parts into the equation $f(x)+f(x+1)=4f(x)$ :

$f(x)+f(x+1)=4f(x)$

$3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x$

Factor the left side

$3^x*(1+3)=4*3^x$

Divide both sides by 3^x

$1+3=4\\4=4$

Because this equation is true, $f(x)+f(x+1)=4f(x)$ is therefore true.

I hope this helps!

3 0

3 years ago

Round off 10256 to the nearest 1000​

Round off 10256 to the nearest 1000