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Digiron [165]
3 years ago
15

Which of the following is the measure of ÐQRS?

Mathematics
2 answers:
luda_lava [24]3 years ago
6 0
I think the answer is D
if not then its C
deff fn [24]3 years ago
4 0
It would be D all the way cause it how far and closest to it
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Given the data below:
Leno4ka [110]

Answer:

5.16

Step-by-step explanation:

Since after x=3, value of y starts decreasing for increasing values of x, let's choose. Also we need to find f(x) for x=3.4

x=3,4,5 and f(x)=7,3,1 to find lagrange polynomial

P(x)= ((x-x2)(x-x3)y1)/((x1-x2)(x1-x3) + ((x-x1)(x-x3)y2)/((x2-x1)(x2-x3) + ((x-x1)(x-x2)y3)/((x3-x1)(x3-x2)

P(x)= ((x-4)(x-5)7)/((3-4)(3-5)) + ((x-3)(x-5)3)/((4-3)(4-5)) + ((x-3)(x-4)1)/((5-3)(5-4))

P(x)= x² -11x+31

P(3.4)= 5.16

7 0
3 years ago
6+n/60=15/90<br><br> How do I dolce this
Lilit [14]
6+\frac{n}{60}=\frac{15}{90}\\\\6+\frac{n}{60}=\frac{1}{6}\ \ \ \ \ |multiply\ both\ sides\ by\ 60\\\\360+n=10\ \ \ \ \ \ \ |subtract\ 360\ from\ both\ sides\\\\\boxed{n=-350}
8 0
3 years ago
Write an equation of the line that passes through each points (5,6) (3.4)
ioda

Answer:

y = x + 1.

Step-by-step explanation:

Start by finding the slope of this line.

If a slanting line goes through (x_{0},\, y_{0}) and (x_{1},\, y_{1}), where x_{0} \ne x_{1}, the slope of this line would be:

\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}}\end{aligned}.

The line in this question goes through (5,\, 6) and (3,\, 4). Hence, the slope of this line would be:

\begin{aligned}m &= \frac{y_{1} - y_{0}}{x_{1} - x_{0}} \\ &= \frac{6 - 4}{5 - 3} \\ &= 1\end{aligned}.

If a slanting line with a slope of m and goes through the point (x_{0},\, y_{0}), the equation of this line in the point-slope form would be:

y - y_{0} = m,\, (x - x_{0}).

For the line in this question, the slope is m = 1. Take (5,\, 6) as the chosen point on this line. The point-slope form equation of this line would be:

y - 6 = (x - 5).

Rewrite to obtain the equation of this line in the slope-intercept form:

y = x + 1.

7 0
3 years ago
3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup = 0, the equation has only one solution.

In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

\bigtriangleup = b^{2} - 4ac

\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

For k = 6 or k = -6, the equation will have exactly one solution.

3 0
3 years ago
Select all that applies!
Serhud [2]

Answer:

C.

Step-by-step explanation:

Because there is constant term 4 in the question, but there is no any such constant term in the given options.

7 0
3 years ago
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