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2 years ago

8 please and thank u

Mathematics

1 answer:

pishuonlain [190]2 years ago

3 0

Answer:

About 5

Step-by-step explanation:

2/3 times 7 is 4.66666666667

Round that up to 5

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Answer:

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Step-by-step explanation:

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2 years ago

Please help, I will give brainliest to whoever helps!

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Which method would you choose to solve the following system?

gladu [14]

Answer: combining like terms

Step-by-step explanation:

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2 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

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3 years ago

Solve for x: 7+4x=13+x

Mnenie [13.5K]

$7+4x=13+x \\\\4x-x=13-7 \\\\3x=6 \\\\\boxed{x=\frac{6}{3}=2}$

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2 years ago

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