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Kamila [148]
3 years ago
9

Please help with question below!

Mathematics
2 answers:
Charra [1.4K]3 years ago
6 0

Answer:

45

Step-by-step explanation:

45 is constant, because no mater how many miles you drive, you will always be charged $45. It stays the same

Ipatiy [6.2K]3 years ago
6 0

Answer:

45

Step-by-step explanation:

your equation would be y= 45+22x and no matter what x equals, you will always have the set $45, so that is your constant.

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The cake store is having a 25\%25%25, percent off sale on all of its cakes.
mina [271]

Answer:

2.25

Step-by-step explanation:

25% is a quarter

therefore a quarter of 9 is

0.25×9

=2.25

7 0
2 years ago
Compute 123x45+246x30+369x15
Arte-miy333 [17]

Answer: 18450

Step-by-step explanation:

7 0
2 years ago
Consider the following pair of equations:
Oksana_A [137]
There is a special kind of substitution which some books call it by comparison.

When the two equations are both 
y=some function of x
y=some other function of x, then
we can substitute the second equation into the first giving
some function of x = some other function of x and start solving.

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<span>y = –2x + 8 
y = x – 1
substitute second into first
x-1=-2x+8
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3x=9
x=3
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5 0
3 years ago
1.The coordinates of the vertices of △RST are R(−4, −1) , S(−1, −1) , and T(−4, −2) .
Tju [1.3M]

RS points east; R'S' points north, so there has been a rotation 90° CCW.

After that rotation, point S would be at (1, -1). It is actually at (1, 1), so has been shifted 2 units upward.

A sequence that does the desired mapping is

  • c. rotation of 90° CCW about the origin
  • b. translation 2 units up

8 0
3 years ago
Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but
grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

\frac{8km}{55min}=.145\frac{km}{min} and we can use that in a d = rt table:

                 d        =        r        *        t

Nina                            .145

Jo

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

                d        =        r       *        t

Nina         6        =     .145

Jo             6        =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

                d        =        r        *        t

Nina          6       =       .145    *      t + 3

Jo              6       =         r       *         t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0
2 years ago
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