All categories

3 years ago

Please help . I’ll mark you as brainliest if correct!

Mathematics

1 answer:

enot [183]3 years ago

8 0

Answer:

$\boxed{\ g(x)=\dfrac{1}{4}|x-2|+1 \ }$

Step-by-step explanation:

As the graph is passing via (2,1) and (-6,3)

$g(x)=\dfrac{1}{4}|x-2|+1$

You might be interested in

I need help ASAP !!!!

Nina [5.8K]

The last option because the range is the input values

6 0

3 years ago

A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat

DiKsa [7]

Answer:

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let $\mu$ be the random variable that follows a Poisson distribution, then mean $\mu = \dfrac{10}{500}= 0.02$

and the mean that the random selection of 50 pages will contain no error is $\lambda = 50 \times 0.02 =1$

∴

$Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}$

Pr(q =0) = 0.368

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2

$P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]$

$P(X \geq 2) = 1 - [0.3678 +0.3678]$

$P(X \geq 2) = 1 -0.7356$

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0

3 years ago

A postal worker counts the number of complaint letters received by the United States Postal Service in a givenday. Identify the

Nata [24]

Answer:

A) quantitative

Step-by-step explanation:

A data that can be counted or expressed numerically constitute quantitative data. Quantitative data collection method is capturing statistical data in numbers, figures, or values. Quantitative data collection usually answered the questions of “how many?”, "how much?" and “how often?” are the occurrence of a particular data. These questions are quantitative data collection methods based on numbers and mathematical calculations. Quantitative data collection methods are based on random sampling and structured data collection. Some of the quantitative data collection methods are surveys, questionnaires, quizzes, interviews and direct observation.

6 0

4 years ago

The weights of adobe bricks used for construction are normally distributed with a mean of 3 pounds and a standard deviation of 0

dedylja [7]

Answer: a) 0.8413, b) 0.9987.

Step-by-step explanation:

Since we have given that

Mean = 3 pounds

Standard deviation = 0.25 pounds

n = 28 bricks

So, (a) What is the probability that all the bricks in the sample exceed 2.75 pounds?

$P(X>2.75)\\\\=P(z>\dfrac{2.75-3}{0.25}\\\\=P(z>\dfrac{-0.25}{0.25})\\\\=P(z>-1)\\\\=0.8413$

b) What is the probability that the heaviest brick in the sample exceeds 3.75 pounds?

$P(X>3.75)\\\\=P(z>\dfrac{3.75-3}{0.25})\\\\=P(z>\dfrac{0.75}{0.25})\\\\=P(z>3)\\\\=0.9987$

Hence, a) 0.8413, b) 0.9987.

4 0

3 years ago

What is the perimeter of this figure, to the nearest unit?

lana66690 [7]

Answer:

P=38

Step-by-step explanation:

At this case I would use the circumference formula for the rounded part.

The formula of the circumference is C=2πr.

So... We know that the radius is 5 which is half of the diameter. So... C=2π5 which is C=10π or C=31.4 which we divide by 4 because on the image is 1/4th of a circle and C/4 which C=7.85 so the P of the whole figure is P=10+10+5+5+7.85 which is P=37.85 which will be P=38.

Answer: P=38

7 0

3 years ago