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3 years ago

Hi guys can I have some help here with year 6 rounding? (Send me screen shot)

Mathematics

1 answer:

alexira [117]3 years ago

5 0

Answer:

nearest ten thousand – 2,620,000

nearest hundred thousand – Two million, six hundred thousand

Step-by-step explanation:

hope this helps.

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What are the coefficients in the expression, 9 - 4 + 3b + 7a?

vodomira [7]

Answer:

The coefficients are b and a

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3 years ago

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Find the values of x and y.

Oliga [24]

Answer:

y=17,x=15

Step-by-step explanation:

180-112=68

68/4=y=17

180-68=112

112-7=105

105/7=x=15

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3 years ago

The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount by p

yawa3891 [41]

500=4πr^2. first divide 500 from four which will equal 125, then divide 125 with π and it will equal 39.788 . finally √39.788. the answer will be r=6.3 or 6

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3 years ago

You draw a card from a deck. If you get a red card, you win nothing. If you get a spade, you win $5. For any club, you win

strojnjashka [21]

Answer:

Standard deviation = 0.547

Step-by-step explanation:

Given the data

$5 for spade

$10 for any club

$20 for an ace club

Lets assume Probability of getting these cards to be

0.5, 0.20 and 0.30

Therefore, mean would be

Summation (PX) = 5×0.5 + 10×0.2 +20×0.3

Summation (PX)/n= 10.5/35 = 0.3

Standard deviation = √0.3

Standard deviation = 0.547

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3 years ago

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The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc

ArbitrLikvidat [17]

Answer:

a) Sample correlation coefficient, r = 0.7411

bi) test statistic, t = 4.102

bii) P-value = 0.000736

Step-by-step explanation:

a) The formula for the sample correlation coefficient is given by the formula:

$r = \frac{S_{xy} }{\sqrt{S_{xx} S_{yy} }} }$

$S_{xx} = 2,648,130.357\\S_{yy} = 36.7376,\\S_{xy} = 7408.225$

$r = \frac{7408.225}{\sqrt{2648130.357*36.7376} }$

r = 0.7511

i) formula for the test statistic is given by the formula:

$t = \frac{r\sqrt{n-1} }{\sqrt{1 - r^{2} } }$

sample size, n = 4

$t = \frac{0.7511\sqrt{14-1} }{\sqrt{1 - 0.7511^{2} } }$

t = 4.102

ii) Degree of freedom, df = n -2

df = 14 -2

df = 12

The P-value is calculate from the degree of freedom and the test statistic using excel

P-value =(=TDIST(t,df,tail))

P-value = (=TDIST(4.1,12,1)

P-value = 0.000736

4 0

3 years ago