Answer:
<em>Answer:</em> <em>A</em> 
Step-by-step explanation:
The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.
Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.
Both triangles are right because they have an internal angle of 90°, so the second condition is also met.
Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.
One of these two conditions should be met:
Side TM is congruent to side OR, or
Side MO is congruent to side RT.
From the available options, only the first is correct.
Answer: A 
Answer:
vertex = (- 1, 3 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
= - 
y = 2x² + 4x + 5 ← is in standard form
with a = 2, b = 4, then
= - 
= - 1
Substitute x = - 1 into the equation for corresponding value of y, that is
y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3
vertex = (- 1, 3 )
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
7:4
or
7/4
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