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3 years ago

The diagonals of a rhombus are 21 m and 32m. what is the area of the rhombus

Mathematics

1 answer:

fredd [130]3 years ago

7 0

With area: multiply width and length

21•32 = 672

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Mary and Roberto go to the movies. They buy a large popcorn for $8.50, and two medium sodas for $4.25. How much did they spend a

alukav5142 [94]

Answer:

$19.15

Step-by-step explanation:

Equation 1: 8.50+4.25+4.25= 17.00 (price of the popcorn and drinks)

Equation 2: 17.00/7.89= 2.15 (how to find how much the tax is)

Solve: 17.00+2.15=19.15 (add the tax to how much the popcorn and drinks were)

6 0

3 years ago

Using data set from 1.19

Dahasolnce [82]

Answer:

Step-by-step explanation:

Honestly I think that is a whole bunch of gibberish

6 0

3 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

Plss can someone help me out with thissss!!!!!!!!!!!

KengaRu [80]

If there aren’t any degrees and it doesn’t state that the triangle is equilateral then you cannot solve this equation without more information

4 0

3 years ago

find three consecutive integers such that the sum of twice he smallest and 3 times the largest is 126.

vladimir1956 [14]

$a,a+1,a+2\ \ -\ three\ consecutive\ integers\\\\
2a+3(a+2)=126\\\\
2a+3a+6=126\\\\
5a+6=126\ \ \ |Subtract\ 6\\\\
5a=120\ \ \ |Divide\ by\ 5\\\\
a=24\\\\Numbers\ are:\ 24,25,26.$

8 0

3 years ago