Answer:the bottom left corner of the triangle should be on the red dot right?
Step-by-step explanation:
sorry if this isn't helpful just trying to help
Solve for x:
10 (x + 2) = 5 (x + 8)
Expand out terms of the left hand side:
10 x + 20 = 5 (x + 8)
Expand out terms of the right hand side:
10 x + 20 = 5 x + 40
Subtract 5 x from both sides:
(10 x - 5 x) + 20 = (5 x - 5 x) + 40
10 x - 5 x = 5 x:
5 x + 20 = (5 x - 5 x) + 40
5 x - 5 x = 0:
5 x + 20 = 40
Subtract 20 from both sides:
5 x + (20 - 20) = 40 - 20
20 - 20 = 0:
5 x = 40 - 20
40 - 20 = 20:
5 x = 20
Divide both sides of 5 x = 20 by 5:
(5 x)/5 = 20/5
5/5 = 1:
x = 20/5
The gcd of 20 and 5 is 5, so 20/5 = (5×4)/(5×1) = 5/5×4 = 4:
Answer: x = 4
Answer:
The rectangular form of ![4[cos(150^{o})+i sin (150^{o})]](https://tex.z-dn.net/?f=4%5Bcos%28150%5E%7Bo%7D%29%2Bi%20sin%20%28150%5E%7Bo%7D%29%5D)
is 
.
To get the graph to have one x-intercept, we must find the m value where the discriminant of the equation will equal 0.
The discriminant for a graph with one x-intercept is found with the following formula:
Plug in the values of the equation into this formula:
Add 144 to both sides:
Square root both sides to get m by itself:
In order for the graph to have one x-intercept, m must equal
-12 or 12.
Answer:
Step-by-step explanation
Perimeter of a rectangle =2(length +breadth)
90m = 2{(36x+2) + (2(x+2)}
Opening the inner brackets,
90 = 2{36x +2+2x +4}
90 = 2{38x +6}
Open the brackets
90 = 76x + 12
Collect like terms
90 - 12 = 76x
78=76x
Divide 78 by the coefficient of x
x = 78÷76
x =1.03m (2d.p)
Substitute the value of x into the expressions for the two sides of the rectangle
36x+2 =(36×1.03) +2= 37.08+2=39.08m
2(x+2)= 2(1.03+2)= 2(3.03) =2×3.03= 6.06m
The approximate values of the two sides of d rectangular field are 39.08m and 6.06m
