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Kisachek [45]
3 years ago
6

Judy, Celia, and Betty are a math teacher, a truck driver, and a housewife, but not necessarily in that

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:

Judy-housewife; Celia-math teacher; Betty-truck driver

Step-by-step explanation:

pls mark me brainliest

Olin [163]3 years ago
6 0

Answer:

Judy is the housewife.

Celia is the math teacher.

Betty is the truck driver.

Step-by-step explanation:

Let's analyze each sentence.

<u>Judy can't drive and is married to the brother of the math teacher.</u>

  • So if she can't drive, she's not the truck driver, and she's not the math teacher if she's married to the math teacher's brother. (Unless-- let's not go there.) Judy is the housewife.

<u>Celia is the best friend of the truck driver.</u>

  • This mean's Celia's not the truck driver - and she's not the housewife, because we decided Judy was the housewife, so Celia is the math teacher.

By process of elimination, Betty is the truck driver.

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Graph the circle 2+ y2 - 14x + 2y + 41 = 0.
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Answer:

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Step-by-step explanation:

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The radius of a sphere is 5 yards. Find the<br> volume of the sphere.
FinnZ [79.3K]

Answer:

V = 523.6 yd³

Step-by-step explanation:

The equation for the volume of a sphere of radius r is

V = (4/3)πr³

and if we substitute 5 yds for r, we get

V = (4/3)*π*(5 yd)³, or

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V = 523.6 yd³

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3 years ago
Mari and Jen each work 20 hours a week at different jobs. Mari earns twice as much as Jen. Together they earn $480. How much doe
Salsk061 [2.6K]
We will call:
M=Mari
J=Jen

Initial equations:

M=2J
M+J=480
(the fact that they work 20 hours a week is not needed in this problem information)

Plug in:
2J+J=480
3J=480
J=160

Jen makes $160 a week.

Therefore:

M=2J
M=2(160)
M=320

Mari makes $320 per week
Jen makes $160 per week
7 0
3 years ago
29867+14938 plz i need help
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Step-by-step explanation:

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In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
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