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Kisachek [45]
3 years ago
6

Judy, Celia, and Betty are a math teacher, a truck driver, and a housewife, but not necessarily in that

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:

Judy-housewife; Celia-math teacher; Betty-truck driver

Step-by-step explanation:

pls mark me brainliest

Olin [163]3 years ago
6 0

Answer:

Judy is the housewife.

Celia is the math teacher.

Betty is the truck driver.

Step-by-step explanation:

Let's analyze each sentence.

<u>Judy can't drive and is married to the brother of the math teacher.</u>

  • So if she can't drive, she's not the truck driver, and she's not the math teacher if she's married to the math teacher's brother. (Unless-- let's not go there.) Judy is the housewife.

<u>Celia is the best friend of the truck driver.</u>

  • This mean's Celia's not the truck driver - and she's not the housewife, because we decided Judy was the housewife, so Celia is the math teacher.

By process of elimination, Betty is the truck driver.

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3 years ago
How much time will Alex need to walk to his school, which is 2 1/4 miles away from his house, if he would walk with the speed of
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Hope this helped!

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3 years ago
Read 2 more answers
A cup of coffee at 93 degrees Celsius is placed in a room at 23 degrees Celsius. Suppose that the coffee cools at a rate of 1 de
Alinara [238K]

Answer:

Step-by-step explanation:

The rate of change of temperature of the coffee with respect to time is expressed by the differential equation

dT/dt=k(T−A) when k = -1 and A = 23. The equation will become:

dT/dt = -(T-23)

If the coffee cools at the rate of 1°C per minute, then dT/dt = -1 and T = 70

Substituting into the equation:

-1 = k(70-23)

-1 = 47k

k = -1/47

k = -0.0213

Substituting k = -0.0213 into the original equation, the differential equation will be:

dT/dt=k(T−A)

dT/dt = -0.0213(T-23)

dT/dt = -0.0213T+0.489

To get the value of T, we will use variable separable method

dt = dT/-0.0213T+0.489

Integrate both sides

t = -0.0213ln(-0.0213T+0.489)

At t = 1 minute

1 = -0.0213ln(-0.0213T+0.489)

1/-0.0213 = ln(-0.0213T+0.489)

-46.95 = ln(-0.0213T+0.489)

Apply exp to both sides

e^-46.95 = e^ln(-0.0213T+0.489)

4.073×10^-21= -0.0213T+0.489

-0.0213T = 4.073×10^-21-0.489

-0.0213T = -0.489

T = 0.489/0.0213

T = 22.96°C

5 0
3 years ago
Please help! I will mark you as brainliest!
aivan3 [116]

Answer:

Area = 12 square centimetres

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