Answer:

Weight of the truck=9408 N
Step-by-step explanation:
Boat is experiencing the buoyant force as it is in the water and is sinking
According to the force balance in y direction. As both is floating, two forces balance each other:

where:
is the buoyant force
is the weight=mg
Eq (1)
Buoyant force is equal to the mass of water displaced * gravitational acceleration.

Taking density of water to be 1000 Kg/m^3

From Eq(1):

Weight of the truck=9408 N
Answer:
12.13
Step-by-step explanation:
Please tell me if I'm correct!
Answer:
see explanation
Step-by-step explanation:
Given f(x) then the derivative f'(x) is
f'(x) = lim(h tends to 0 ) 
= lim ( h to 0 ) 
= lim ( h to 0 ) 
= lim( h to 0 ) 
= lim( h to 0 ) 
= lim ( h to 0 )
← cancel h on numerator/ denominator
= lim ( h to 0 ) 4(2x + h) ← let h go to zero
f'(x) = 8x
10.47 bushels
3(349/100)= 10.47