Evaluate 2r²+3s³-r²+4+²-r²

2 answers:

7 0

$2r^2 + 3s^3-r^2+4^2+-r^2 \\ \\ 2r^2 + 3s^3 - r^2 + 16 + -r^2 \\ \\ 2r^2 + 3s^3 = r^2 16 - r^2 \\ \\ (2r^2 - r^2-r^2) + 3s^3+ 16 \\ \\ 3s^3 + 16 \\ \\ Answer: 3s^3 + 16$

NemiM [27]2 years ago

3 0

$2r^2 + 3s^3 -r^2 + 4^2 - r^2\\\\2r^2 -r^2 -r^2 + 3s^3 + 4^2\\\\3s^3 + 4^2\\\\\boxed{\bf{3s^3+16}}$

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