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bekas [8.4K]
3 years ago
5

Evaluate 2r²+3s³-r²+4+²-r²

Mathematics
2 answers:
Vilka [71]3 years ago
7 0
2r^2 + 3s^3-r^2+4^2+-r^2 \\ \\ 2r^2 + 3s^3 - r^2 + 16 + -r^2 \\ \\ 2r^2 + 3s^3 = r^2 16 - r^2 \\ \\ (2r^2 - r^2-r^2) + 3s^3+ 16 \\ \\ 3s^3 + 16 \\ \\ Answer: 3s^3 + 16
NemiM [27]3 years ago
3 0
2r^2 + 3s^3 -r^2 + 4^2 - r^2\\\\2r^2 -r^2 -r^2 + 3s^3 + 4^2\\\\3s^3 + 4^2\\\\\boxed{\bf{3s^3+16}}
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Answer:

c. domain: {-2, 0, 2}, range: {-1, 1, 3}

Step-by-step explanation:

Given:

There are three points on the graph.

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The points are (-2,-1),(0,1),\textrm{ and }(2,3)

Domain is the set of all possible x values. Here, the x values are -2, 0 and 2.

So, domain is: {-2, 0, 2}.

Range is set of all possible y values. Here, the y values are -1, 1 and 3.

So, range is: {-1, 1, 3}

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Answer:

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A hat salesman earns a commission of 30% of all hat sales made. Yesterday he sold 3 hats for $90 each and 4 hats for $50 each. H
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6 0
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Solving for x,
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Thus, the answer is the second among the choices. 

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6 0
3 years ago
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Step-by-step explanation:

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2 years ago
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