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bekas [8.4K]
3 years ago
5

Evaluate 2r²+3s³-r²+4+²-r²

Mathematics
2 answers:
Vilka [71]3 years ago
7 0
2r^2 + 3s^3-r^2+4^2+-r^2 \\ \\ 2r^2 + 3s^3 - r^2 + 16 + -r^2 \\ \\ 2r^2 + 3s^3 = r^2 16 - r^2 \\ \\ (2r^2 - r^2-r^2) + 3s^3+ 16 \\ \\ 3s^3 + 16 \\ \\ Answer: 3s^3 + 16
NemiM [27]3 years ago
3 0
2r^2 + 3s^3 -r^2 + 4^2 - r^2\\\\2r^2 -r^2 -r^2 + 3s^3 + 4^2\\\\3s^3 + 4^2\\\\\boxed{\bf{3s^3+16}}
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