Evaluate 2r²+3s³-r²+4+²-r²

2 answers:

7 0

$2r^2 + 3s^3-r^2+4^2+-r^2 \\ \\ 2r^2 + 3s^3 - r^2 + 16 + -r^2 \\ \\ 2r^2 + 3s^3 = r^2 16 - r^2 \\ \\ (2r^2 - r^2-r^2) + 3s^3+ 16 \\ \\ 3s^3 + 16 \\ \\ Answer: 3s^3 + 16$

NemiM [27]2 years ago

3 0

$2r^2 + 3s^3 -r^2 + 4^2 - r^2\\\\2r^2 -r^2 -r^2 + 3s^3 + 4^2\\\\3s^3 + 4^2\\\\\boxed{\bf{3s^3+16}}$

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Find the greatest common factor of the following monomials: 20a 46a^2 48a^6

Ierofanga [76]

60a^5 is the answer to your question

6 0

2 years ago

Please help !!!!!!! Will mark brainliest for the correct answer !!!!!!!!

Sholpan [36]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$