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Drupady [299]
3 years ago
7

Bonds with a face value of $744000 and a quoted price of 98.5 have a selling price of

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:

67.91

Step-by-step explanation:

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2= 5 j -28 one or two step equation
Ksenya-84 [330]

Answer:

j=6

Step-by-step explanation:

2=5j-28

+28  +28

30=5j

/5    /5

j=6  

7 0
3 years ago
A fair number cube marked 1, 2, 3, 4, 5, and 6 is rolled. What is the chance that an even number will be rolled?
olchik [2.2K]

Answer:

50% or 1/2

Step-by-step explanation:

Chance is like probability, so the chance of rolling a even number out of  1, 2, 3, 4, 5, and 6 is half of them, they are 2, 4, and 6. In fraction form it is 1/2, and in percent form it is %0%. Hope this helps.

6 0
3 years ago
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What are appropriate ways of write "6 times x"?
Nana76 [90]
Huh what do you mean??
7 0
2 years ago
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Jim ordered a sports drink and three slices of pizza for $8.50. His friend ordered two sports drinks and two slices of pizza for
vagabundo [1.1K]

Answer:

total is 16.50

Step-by-step explanation:

add 8.50+8.00

8 0
3 years ago
In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
3 years ago
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