As The Line 3x + y > 1 involves the inequality ( > ) :
✿ The Shaded Area of the Line 3x + y > 1 is Away from the Origin
✿ The Line 3x + y > 1 is represented by a Dotted Line
As The Line y ≤ x + 2 involves the inequality ( ≤ ) :
✿ The Shaded Area of the Line y ≤ x + 2 is Towards from the Origin
✿ The Line y ≤ x + 2 is represented by a Dark Line.
So, The Graph which fulfills the above Conditions is :
V =
- Exact answer
128 * 3.14 = 401.92 approximate
9514 1404 393
Answer:
sin -12/13
Step-by-step explanation:
You can use the identity ...
tan = sin/cos
to solve for sine:
sin = cos·tan
sin = (-5/13)(12/5) =
sin -12/13
For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
