Since the areas are the same (5 x 6 = 30 units), and the height of the triangle (DC) is 5 so the length of the triangle must be 12. (1/2 of 5 x 12 is also 30)
So now we use the Pythagorean theorem
a² + b² = c² we have 5² + 12² = c² or 25 + 144 = c² or 169 = c²
The square root of 169 is 13 so side DE is 13 units.
84,75,90,87,99,91,85,88,76,92,94
Maslowich
Thank you for the free points
Well there are 2 pecks in 1 kenning
So that's 2 × 1 peck = 1 kenning
2 kennings in 1 bushel
That's 2 × 1 kenning = 1 bushel
2 bushels in 1 strike
That's 2 × 1 bushel = 1 strike
4 strikes in 1 quarter
That's 4 × 1 strike = 1 quarter
4 quarters in 1 chaldron
That's 4 × 1 quarter = 1 chaldron
So now substitute again and again:
4 × 1 quarter = 1 chaldron
4 × ( 4 × 1 strikers ) = 1 chaldron
4 × ( 4 × ( 2 × 1 bushel ) ) = 1 chaldron
4 × ( 4 × ( 2 × ( 2 × 1 kenning ) ) ) = 1 chaldron
4 × ( 4 × ( 2 × ( 2 × ( 2 × 1 peck ) ) ) ) = 1 chaldron
4×4×2×2×2 peck = 1 chaldron
128 peck = 1 chaldron
So that's 128 × 1 peck = 1 chaldron.
Hope this helps.
Answer:
Step-by-step explanation:
Remark
This is actually a six sided figure. That really doesn't matter, but it's interesting to observe. It goes a long way to explaining what is going on. The trick to exterior angles is that as long as the figure is convex ( a closed figure whose lines do not cross), the exterior angles add to 360.
Once you know that, then you know that this figure must have 6 exterior angles and no matter how they are made, their total is 360.
Equation
n + n + n + n + 90 + 90 = 360 Combine like terms.
Solution
4n + 180 = 360 Subtract 180
4n = 360 - 180
4n = 180 Divide both sides by 4
4n/4 = 180/4
n = 45
Note
Not a simple problem. Thanks for posting