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adoni [48]
3 years ago
12

NEED HELP PLEASE IM BEGGING YOU PLEASE!!! NEED HELP ON ALL OF THEM PLEASE!!!!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

B, F, B

Step-by-step explanation:

This is like pre algebra it's not that hard

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\huge\bold\red{{Answer:}}

1.C

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7 0
3 years ago
0.2x - 1 = -1<br> Fndndndnddsmsmsskaalamakaksnsndnx c cncjxmdnd
Sedaia [141]

Answer:

0.2

Step-by-step explanation:

6 0
3 years ago
What is -4 the square root of 12 + the square root of 75 in simplist radical form?
Fofino [41]

Answer:

<u>The simplest radical form of this mathematical expression is - 3√3</u>

Step-by-step explanation:

1. Let's write in a mathematical expression the information given:

-4 the square root of 12 + the square root of 75

-4 (√12) + √75

-4 (√4 * 3) + (√25 * 3)  (12 = 4 * 3 and 75 = 25 * 3)

-4 (2 √3) + 5 √3

-8 √3 + 5√3

- 3 √3

The result is- 3 square root of 3.

<u>The simplest radical form of this mathematical expression is - 3√3</u>

7 0
3 years ago
Urgent I don't have time pllllllllzzzzzzzzzz<br> thhhxx
Elis [28]
I think its the first one
4 0
3 years ago
Read 2 more answers
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
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