Question

Does anyone know how to do the rest?​

Answer 1

Answer/Step-by-step explanation:

Given:

$\frac{4}{x} - \frac{3}{y} = 1$ ---› Equation 1

$\frac{8}{x} + \frac{9}{y} = 7$ ---› Equation 2

Solution:

✔️Equation 1 × 3:

$\frac{4}{x}*3 + \frac{3}{y}*3 = 1*3$

$\frac{12}{x} + \frac{9}{y} = 3$ ---› Equation 3.

✔️Equation 2 + Equation 3:

$\frac{8}{x} + \frac{9}{y} = 7$ ---› Equation 2

$\frac{12}{x} + \frac{9}{y} = 3$ ---› Equation 3.

Thus:

$\frac{-4}{x} = 10$

Cross multiply

$10x = -4$

Divide both sides by 10

$x = -\frac{4}{10}$

$x = -\frac{2}{5}$

✔️Find y:

Substitute x = -2/5 into equation 1

$\frac{4}{x} - \frac{3}{y} = 1$ ---› Equation 1

$\frac{4}{\frac{-2}{5}} - \frac{3}{y} = 1$

$\frac{4}*{\frac{5}{-2}} - \frac{3}{y} = 1$

$-10 - \frac{3}{y} = 1$

Add 10 to both sides

$- \frac{3}{y} = 1 + 10$

$\frac{-3}{y} = 11$

Cross multiply

$11y = -3$

Divide both sides by 11

$y = -\frac{3}{11}$