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antiseptic1488 [7]
3 years ago
5

the length of a new rectangular playing field is 7 yards longer than double the width. if the perimeter of the rectangular playi

ng field is 290 yards, what are its dimensions?
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

the width is 46 and the length is 99

Step-by-step explanation:

perimeter = 290 yards

length =2w+7

width =w

perimeter = 2w + 2l =290

2w+ 2(2w+7) =290

2w+4w+14= 290

6w = 276

w= 46

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Answer:

L = 6 --- Length

W = 4.5 --- Width

Step-by-step explanation:

Given

Let: L = Length; W = Width

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L = 2W- 3m

Required

Find the dimensions of the rectangle

Area (A) is calculated as:

A  = L * W

This gives:

27 = (2W - 3) * W

Open bracket

27 = 2W^2 - 3W

Express as a quadratic function

2W^2 - 3W - 27 = 0

Expand

2W^2 + 6W - 9W - 27 = 0

Factorize:

2W(W + 3) - 9(W + 3) = 0

(2W - 9)(W + 3) = 0

This gives:

2W - 9 = 0\ or\ W + 3 = 0

2W = 9 \ or\ W = -3

Width can not be negative.

So:

2W = 9

W = 4.5

Recall that:

L = 2W- 3m

L = 2 * 4.5 - 3

L = 6

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2 years ago
Can Someone Please Help Me With This Problem.​
34kurt

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Step-by-step explanation:

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