Question

2loga + 4logb - logc - 3logd

Answer 1

Answer: I am sorry I have no idea what this is

Step-by-step explanation: It might be log parenthesis a to the power of 2 than b to the power of 4 over cd to the power of 3 parenthesis have a nice day, hope it is not to confusing, it did not let me use the right characters

Answer 2

Answer:

$log \left( \frac{a^2\,\,b^4}{c\,\,d^3} \right)$

Step-by-step explanation:

We use the properties of logarithms to write this as a single logarithmic expression. First the exponent property:

  2 log(a) + 4 log(b) - log(c) - 3 log(d) =

= log(a^2) + log(b^4) - log(c) - log(d^3) =

and now the multiplication and division properties

= $log \left( \frac{a^2\,\,b^4}{c\,\,d^3} \right)$