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2 years ago

2loga + 4logb - logc - 3logd

Mathematics

2 answers:

lidiya [134]2 years ago

6 0

Answer: I am sorry I have no idea what this is

Step-by-step explanation: It might be log parenthesis a to the power of 2 than b to the power of 4 over cd to the power of 3 parenthesis have a nice day, hope it is not to confusing, it did not let me use the right characters

Blizzard [7]2 years ago

5 0

Answer:

$log \left( \frac{a^2\,\,b^4}{c\,\,d^3} \right)$

Step-by-step explanation:

We use the properties of logarithms to write this as a single logarithmic expression. First the exponent property:

2 log(a) + 4 log(b) - log(c) - 3 log(d) =

= log(a^2) + log(b^4) - log(c) - log(d^3) =

and now the multiplication and division properties

= $log \left( \frac{a^2\,\,b^4}{c\,\,d^3} \right)$

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Chose the correct property

vodka [1.7K]

Answer:

B) Associative Property of Multiplication

Step-by-step explanation:

The associative property states you can change where the parentheses (grouping terms) are in a multiplication statement, and you'll get the same product.

More generally:

(a * b) * c = a * (b * c)

3 0

2 years ago

Read 2 more answers

Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0

fomenos

• The value of the discriminant ,D= -16

• The solution to the quadratic equation is

$x=\frac{1+2i}{5}\text{ or }\frac{1-2i}{5}$

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

$x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}$

Note that:

√-1 = i

$x=\frac{2\pm\sqrt[]{16\times-1}}{10}$

$x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}$ $x=\frac{2\pm4i}{10}$ $x=\frac{2}{10}\pm\frac{4i}{10}$ $x=\frac{1}{5}\pm\frac{2}{5}i$ $x=\frac{1\pm2i}{5}$

That is;