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2 years ago

The sum of 5 consecutive numbers is 200. What is the smallest number?

Mathematics

2 answers:

Vikentia [17]2 years ago

6 0

Answer:

Hey!

Your answer is 44!

Step-by-step explanation:

Here's how...

x+(x+2)+(x+4)+(x+6)+(x+8)=200

5x+20=200 (minus 20 on both sides to get 5x by itself)

5x=180 (divide both sides by 5 to get just x)

x=36

5th number - x+8=36+8=44 (simple substitution and addition)

I HOPE THIS HELPS!

AVprozaik [17]2 years ago

5 0

Answer:

Step-by-step explanation:

let x-2,x-1,x,x+1,x+2 be five consecutive numbers and x-2 is smallest number.

x-2+x-1+x+x+1+x+2=200

5x=200

x=200/5=40

x-2=40-2=38

smallest number is 38

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An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

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Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

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2 years ago

The sum of 5 consecutive numbers is 200. What is the smallest number?​

The sum of 5 consecutive numbers is 200. What is the smallest number?