Option B is correct.
John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide.
Here, 65.25" is Quantitative, continuous
There are two types of quantitative data or numeric data: continuous and discrete.
As a general rule, counts are discrete and measurements are continuous. A continuous data can be recorded at many different points (length, size, width, time, temperature, etc.)
So, option B is the answer.
Answer:
Step-by-step explanation:
you can use the equation point-slope of a line
(y-y1)= m(x-x1)
m is the slope =rise /run
to get from the lower point on the line to the other you rise 4 units and run -6 units so m= -4/6= -2/3
now that you have the slope pick you need one point
pick any poin on the line for example (-4, -1)
now you substitute into the point-slope equation point (-4,-1) and slope -2/3
(y+1)= -2/3(x+4)
in standard form will be
y=
y=
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
147
Step-by-step explanation:
Suplementary angles add up to be 180
So 180-33 is 147
