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3 years ago

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Which of the fraction below is equivalent to 1/3? Show why that fraction is equivalent to 1/3. 4/5, 4/6, 4/9, 4/12

1 answer:

lbvjy [14]3 years ago

4 0

4/12 = 1/3 this would help

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You roll 2 dice. how likely is it that the 2 numbers will add up to 12 or less?

VashaNatasha [74]

It is a very high probability. If you role two dice no matter what you will get 12 or less.

5 0

3 years ago

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2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

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3 years ago

Alguien me puede ayudar a resolver el reto que dejaron hoy en la tele de Matemáticas? Pls urgente

oee [108]

4 bc of the words you know

6 0

3 years ago

GIVING 15 POINTS!!! PLEASE HELP

Lena [83]

1) |−11| = 11, therefore Peter is at a distance of 11 feet

2) Jimmy, because each of the two points is fraction 5 over 8 unit away from 0

3) 36 + 28=64 4x4=36+4x7=28 36+28=64

7+9=16 4x16=64

6 0

3 years ago

5x−2(x+1)=1/4 find x pretty please

disa [49]

Answer:

$\huge\boxed{\bf\:x = \frac{3}{4}}$

Step-by-step explanation:

$5x - 2(x+1)=\frac{1}{4}$

Use the distributive property for 2(x + 1).

$5x - 2x - 2= \frac{1}{4}$

Subtract 2x from 5x.

$3x - 2= \frac{1}{4}$

Bring 2 to the right hand side of the equation .

$3x = \frac{1}{4} + 2$

Add 1/4 & 2.

$3x = \frac{1}{4} + \frac{8}{4} \: \: [LCM = 4]\\3x = \frac{9}{4}$

Now, bring 3 to the right hand side of the equation .

$x = \frac{9}{4} \times \frac{1}{3}\\x = \frac{9}{12}\\\boxed{\bf\:x = \frac{3}{4}}$

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6 0

2 years ago

Read 2 more answers