Question

The heights of the trees in a forest are normally distributed, with a mean of 25 meters and a standard deviation of 6 meters. What is the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters? Use the portion of the standard normal table given to help answer the question.

Answer 1

$\mathbb P(X>37)=\mathbb P\left(\dfrac{X-25}6>\dfrac{37-25}6\right)=\mathbb P(Z>2)$

Since roughly 95% of a normal distribution lies within two standard deviations of the mean, you know that about 5% lies without, and since the distribution is symmetric, you can expect about 2.5% of the distribution to lie above two standard deviations from the mean. So the probability is about $0.025$

If you want more precision, the actual value is closer to $0.0228$.

Answer 2

Answer:

its C 2.3

Step-by-step explanation:

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