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just olya [345]
3 years ago
8

Use absolute value to describe the relationship between a negative credit card balance and the amount owed.

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0
-$<span>25 balance does not mean you have </span>$<span>25 credit but that you owe </span>$25, the absolute value of -$<span>25. Just like the absolute value of 5 would be -5. its just the opposite.</span>
IRINA_888 [86]3 years ago
8 0

Answer:

Negative credit card balance means you owe money from the financial Institution , which is represented by Negative Integer.

Integer={-------,-4,-3,-2,-1,0,1,2,3,4,......}

          =Set of Positive Natural numbers ,Natural numbers having Negative sign behind it and Zero included in this set of numbers.

Suppose You owe $2500 from the bank, which means credit card shows negative balance if represented in terms of integers it will be = -2500

Absolute value of any integer is positive.

|x|=|-x|=x

|-2500|=2500

If Amount owed is $ A, Represented in terms of Integer= -A

Absolute Value of |-A|=A

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1. First we are going to find the vertex of the quadratic function f(x)=2x^2+8x+1. To do it, we are going to use the vertex formula. For a quadratic function of the form f(x)=ax^2+bx +c, its vertex (h,k) is given by the formula h= \frac{-b}{2a}; k=f(h).

We can infer from our problem that a=2 and b=8, sol lets replace the values in our formula:
h= \frac{-8}{2(2)}
h= \frac{-8}{4}
h=-2

Now, to find k, we are going to evaluate the function at h. In other words, we are going to replace x with -2 in the function:
k=f(-2)=2(-2)^2+8(-2)+1
k=f(-2)=2(4)-16+1
k=f(-2)=8-16+1
k=f(-2)=-7
k=-7
So, our first point, the vertex (h,k) of the parabola, is the point (-2,-7).

To find our second point, we are going to find the y-intercept of the parabola. To do it we are going to evaluate the function at zero; in other words, we are going to replace x with 0:
f(x)=2x^2+8x+1
f(0)=2(0)^2+(0)x+1
f(0)=1
So, our second point, the y-intercept of the parabola, is the point (0,1)

We can conclude that using the vertex (-2,-7) and a second point we can graph f(x)=2x^2+8x+1 as shown in picture 1.

2. The vertex form of a quadratic function is given by the formula: f(x)=a(x-h)^2+k
where
(h,k) is the vertex of the parabola.

We know from our previous point how to find the vertex of a parabola. h= \frac{-b}{2a} and k=f(h), so lets find the vertex of the parabola f(x)=x^2+6x+13.
a=1
b=6
h= \frac{-6}{2(1)}
h=-3
k=f(-3)=(-3)^2+6(-3)+13
k=4

Now we can use our formula to convert the quadratic function to vertex form:
f(x)=a(x-h)^2+k
f(x)=1(x-(-3))^2+4
f(x)=(x+3)^2+4

We can conclude that the vertex form of the quadratic function is f(x)=(x+3)^2+4.

3. Remember that the x-intercepts of a quadratic function are the zeros of the function. To find the zeros of a quadratic function, we just need to set the function equal to zero (replace f(x) with zero) and solve for x.
f(x)=x^2+4x-60
0=x^2+4x-60
x^2+4x-60=0
To solve for x, we need to factor our quadratic first. To do it, we are going to find two numbers that not only add up to be equal 4 but also multiply to be equal -60; those numbers are -6 and 10.
(x-6)(x+10)=0
Now, to find the zeros, we just need to set each factor equal to zero and solve for x.
x-6=0 and x+10=0
x=6 and x=-10

We can conclude that the x-intercepts of the quadratic function f(x)=x^2+4x-60 are the points (0,6) and (0,-10).

4. To solve this, we are going to use function transformations and/or a graphic utility.
Function transformations.
- Translations:
We can move the graph of the function up or down by adding a constant c to the y-value. If c\ \textgreater \ 0, the graph moves up; if c\ \textless \ 0, the graph moves down.

- We can move the graph of the function left or right by adding a constant c to the x-value. If c\ \textgreater \ 0, the graph moves left; if c\ \textless \ 0, the graph moves right.

- Stretch and compression:
We can stretch or compress in the y-direction by multiplying the function by a constant c. If c\ \textgreater \ 1, we compress the graph of the function in the y-direction; if 0\ \textless \ c\ \textless \ 1, we stretch the graph of the function in the y-direction.

We can stretch or compress in the x-direction by multiplying x by a constant c. If c\ \textgreater \ 1, we compress the graph of the function in the x-direction; if 0\ \textless \ c\ \textless \ 1, we stretch the graph of the function in the x-direction.

a. The c value of f(x) is 2; the c value of g(x) is -3. Since c is added to the whole function (y-value), we have an up/down translation. To find the translation we are going to ask ourselves how much should we subtract to 2 to get -3?
c+2=-3
c=-5

Since c\ \textless \ 0, we can conclude that the correct answer is: It is translated down 5 units.

b. Using a graphing utility to plot both functions (picture 2), we realize that g(x) is 1 unit to the left of f(x)

We can conclude that the correct answer is: It is translated left 1 unit.

c. Here we have that g(x) is f(x) multiplied by the constant term 2. Remember that We can stretch or compress in the y-direction (vertically) by multiplying the function by a constant c.

Since c\ \textgreater \ 0, we can conclude that the correct answer is: It is stretched vertically by a factor of 2.

4 0
3 years ago
Find each sum or difference. Show your work. <br><br> a^2+5a-3-(2a^2-4a+3)<br><br> Plz help!
anzhelika [568]
Hey there :)

( a² + 5a - 3 ) - ( 2a² - 4a + 3 )

Combine like-terms

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- a² + 9a - 6
6 0
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