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jek_recluse [69]
3 years ago
6

Write the sentence as an equation.

Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

b x 390 =339

Step-by-step explanation:

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What is 8/10 simplified
Viefleur [7K]
The answer is 4/5 in the simplest form.
3 0
3 years ago
Read 2 more answers
Please help i have been struggling with this
Readme [11.4K]

Answer:

When put into a decimal, the answer is 0.09 recurring.

Step-by-step explanation:

Divide the numerator by the denominator to convert a fraction to a decimal. The entire number stays to the left of the decimal when there is a mixed number.

4 0
2 years ago
Steven earns extra money babysitting he charges $33 for 4 hours and $57.75 for 7 hours entering an equation to represent the rel
sweet [91]

Answer:

<em>y = 8.25x</em>

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If a situation comes where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

y=mx+b

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Let's use linear modeling to represent Steven's earnings he makes babysitting. Call y the money he charges by x hours of work.

We know he charges y1=$33 for x1=4 hours, and y2=$57.75 for x2=7 hours. The ordered pairs are (4,33) and ( 7, 57.75)

Computing the equation of the line we have:

\displaystyle y-33=\frac{57.75-33}{7-4}(x-4)

Operating:

\displaystyle y-33=\frac{24.75}{3}(x-4)

y - 33 = 8.25( x - 4 )

y = 8.25x - 33 + 33

y = 8.25x

There is a proportional relationship.

6 0
3 years ago
Differentiate y = 8x/ 3 − tan(x)
vagabundo [1.1K]

Answer:

\frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}

Step-by-step explanation:

y=\frac{8x}{3-tan(x)}\\ \\\frac{dy}{dx}=\frac{(3-tan(x))(\frac{d}{dx}8x)-(\frac{d}{dx}(3-tan(x)))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{(3-tan(x))(8)-(-sec^2(x))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{24-8tan(x)+8xsec^2(x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{8xsec^2(x)-8tan(x)+24}{(3-tan(x))^2}\\\\ \frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}

Remember to use the Quotient Rule

4 0
2 years ago
Evaluate the expression when c=-6 <br> c^2+7c-5
xz_007 [3.2K]
 -5.16666667
first you have to subtract c from both sides.
0=-6^2+6c-5
0=36+6c-5
0=31+6c
then subtract 31 from both sides.
-31=6c
then -31 divided by 6
8 0
4 years ago
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