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jasenka [17]
3 years ago
15

Twenty-five students go to lunch. Pizza costs $3 and sandwiches cost $2. Twelve students buy pizza. What is the total amount of

money spent on sandwiches?
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
4 0
25 students
Pizza - $3
Sandwiches - $2

12 students  x  $3 Pizza = $36
25 students   -  12 students = 13 students bought sandwiches

13 students  x  $2 sandwiches =
$26 spent on sandwiches.

I hope this helps!
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Im stuck on this question, Please help!
Alexxx [7]
= (x^18y^24)/(x^2y^2)

Simplified = x^16y^22

The last answer is correct (x^16y^22)
3 0
3 years ago
Solve each problem and check your answer using estimates. a. $18.79 + $2.11 + ‐$1.92 + $17.28 b. $7.45 + ‐$24.45 + $74.17 + ‐$76
Aneli [31]

The solution to the linear expressions are:

  • a. $36.26
  • b. -$19.35
  • c. $70.38

<h3>Solving linear expressions:</h3>

The solution to linear expression is determined by taking into consideration the arithmetic operations used in each linear expression.

From the information given:

a. $18.79 + $2.11 + ‐$1.92 + $17.28

By rearrangement:

= $18.79 + $2.11 + $17.28 ‐$1.92

= $36.26

b. $7.45 + ‐$24.45 + $74.17 + ‐$76.52

By rearrangement:

= $7.45  + $74.17 ‐ $24.45 ‐ $76.52

= -$19.35

c.  $98.45 − $10.63 + $2.82 − $20.26

By rearrangement:

= $98.45 + $2.82 − $10.63 − $20.26

= $70.38

Learn more about solving linear expressions here:

brainly.com/question/2030026

#SPJ1

7 0
1 year ago
-(14-2y) +3y+26 how do i find y
Setler79 [48]
Y is behind 2 its in plain sight   
7 0
3 years ago
In △ABC, angle C is a right angle and BC &gt; AC. Select all the statements that are true.
Alexus [3.1K]

△ABC  right angle C, leg BC > leg AC.  So angle A > angle B.

a=BC, b=AC, c=AB

a > b

sin A= cos B = a/c

sin B = cos A = b/c

a = c sin A = c cos B

b = c sin B = c cos A

a > b

c sin A > c sin B

sin A > sin B

c cos B > c cos A

cos B > cos A

Answer:  B, E

7 0
3 years ago
Dorothy Little purchased a mailing list of 2,000 names and addresses for her mail order business, but after scanning the list sh
andrew-mc [135]

Answer:

P(X > 0) = 0.9222

Step-by-step explanation:

For each name, there are only two outcomes. Either the name is authentic, or it is not. So, we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem.

5 names are selected, so n = 5

A success is a name being non-authentic. 40% of the names are non-authentic, so \pi = 0.40.

We have to find P(X > 0)

Either the number of non-authentic names is 0, or is greater than 0. The sum of these probabilities is decimal 1. So:

P(X = 0) + P(X > 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{5,0}*(0.40)^{0}*(0.6)^{5} = 0.0778

So

P(X > 0) = 1 - P(X = 0) = 1-0.0778 = 0.9222

5 0
3 years ago
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