Formula for perimeter of a rectangle is:
P = 2 * (a+b)
This means that sum of two sides is:
64 = 2* (a+b)
a+b=32
Pairs of numbers that add to 32 are:
1+31
2+30
3+29
4+28
5+27
6+26
7+25
8+24
9+23
10+22
11+21
12+20
13+19
14+18
15+17
16+16
We do not consider last pair as it would represent square. Areas these sides cover are:
1*31=31
2*30=60
3*29=87
4*28=112
5**27=135
6*26=156
7*25=175
8*24=192
9*23=207
10*22=220
11*21=231
12*20=240
13*19=247
14*18=252
15*17=255
Maximum area is 255 and lengths of sides are 15 and 17. This answer makes sense because larger sides give larger area.
Answer:
x < 33.84
Step-by-step explanation:
we have
13.48x-200 < 256.12
Solve for x
Adds 200 both sides
13.48x-200 +200 < 256.12+200
13.48x < 456.12
Divide by 13.48 both sides
13.48x/13.48 < 456.12/13.48
x < 33.84
The solution is the interval ----> (-∞, 33.84)
All real numbers less than 33.84
Answer:
Therefore the required equation is
Y=5+3X
Step-by-step explanation:
Given that , Joey has 5 collector stamps.
He gets 3 more stamps each week.
The number of week is X.
1st week he got 3 stamps
2nd week he got (3+3)=2.3 stamps
3rd week he got (3+3+3)=3.3 stamps
Stamp that he got=( the number of week ×3)
Therefore at end of Xth week he got =(X × 3) =3X stamps
Total number of stamps that collected after x week
=5+3X
Therefore the required equation is
Y=5+3X
I hope this helps you
16 and 19 prime number and they can common divide only 1 gcf 1