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noname [10]
3 years ago
8

What do you suppose you're supposed to do here

Mathematics
1 answer:
kumpel [21]3 years ago
5 0
Count how many squares are shaded in and choose the corresponding fraction i guess?
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Jade takes 5 minutes more than twice as long as Binh to ride to their friend’s house. If Binh takes x minutes to ride to his fri
skad [1K]

Answer:

It will take Jade (2x + 5) minutes

Step-by-step explanation:

Let us find the expression that represents the time Jade will take

∵ Binh takes x minutes to ride to his friend’s house

∴ The time Binh takes = x minutes

∵ 5 more means + 5

∵ Twice means × 2

∵ Jade takes 5 minutes more than twice as long as Binh to ride to their

   friend’s house

→ Multiply the time Binh takes by 2 and add the product by 5

∵ Binh takes x minutes

∴ The time Jade takes = 2 × x + 5

∴ The time Jade takes = 2x + 5 minutes

∴ It will take Jade (2x + 5) minutes

6 0
3 years ago
Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.
Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

6 0
3 years ago
Which type of factoring is used to factor the following expression:<br> 2x^2 + 7x- 30
svetlana [45]

Answer:

 (2x - 5) • (x + 6)

7 0
3 years ago
11z/16+7z/8=5/16 as a decimal
babunello [35]
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
4 0
2 years ago
Please answer all parts of the question and all work shown.
faust18 [17]

Answer:

a. 0.4931

b. 0.2695

Step-by-step explanation:

Given

Let BG represents Boston Globe

NYT represents New York Times

P(BG) = 0.55

P(BG') = 1 - 0.55 = 0.45

P(NYT) = 0.6

P(NYT') = 1 -0.6 = 0.4

Number of headlines = 5

Number of depressed articles = 3 (at most)

a.

Let P(Read) = Probability that he reads the news the first day

P(Read) = P(He reads BG) and P(He reads NYT)

For the professor to read BG, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(BG = 4) is given as the binomial below

(BG + BG')^n where n = 5, r = 4

So, P(BG = 4) = C(5,4) * 0.55⁴ * 0.45¹

P(BG = 5). = (BG + BG')^n where n = 5, r = 5

So, P(BG = 5) = C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3)= 1 - P(BG = 4) - P(BG = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.55⁴ * 0.45¹ - C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3) = 0.7438

For the professor to read NYT, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(NYT = 4) is given as the binomial below

(NYT+ NYT')^n where n = 5, r = 4

So, P(NYT = 4) = C(5,4) * 0.6⁴ * 0.4¹

P(NYT = 5). = (NYT + NYT')^n where n = 5, r = 5

So, P(NYT = 5) = C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3)= 1 - P(NYT = 4) - P(NYT = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.6⁴ * 0.4¹ - C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3) = 0.6630

P(Read) = P(He reads BG) and P(He reads NYT)

P(Read) = 0.7438 * 0.6630

P(Read) = 0.4931

b.

Given

n = Number of week = 7

P(Read) = 0.4931

R(Read') = 1 - 0.4931 =

He needs to read at least half the time means he reads for 4 days a week

So,

P(Well-informed) = (Read + Read')^n where n = 7, r = 4

P(Well-informed) = C(7,4) * (0.4931)⁴ * (1-0.4931)³ = 0.2695

3 0
2 years ago
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