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2 years ago

Solve 2tan(x)cos^2(x)=1 algebraically

Mathematics

1 answer:

deff fn [24]2 years ago

7 0

X= pi/4 +k(pi)
(This may not be correct sorry)

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HELP THIS IS DUE TODAY

masya89 [10]

Answer:

7) circumference = 11.78 ft

8) arc NMP = 198° or 27.63 ft

Step-by-step explanation:

7) circumference = πd = (3.14) (3 3/4) = 11.78 ft

8) radius = 8 ft

diameter = 2 x 8 = 16 ft

arc NM + arc QP = 360° - 162° - 162° = 36°

arc NM = arc QP because they are arcs of vertical angles.

arc QP = 18°

arc NMQ = 180°

arc NMP = 180° + 18° = 198°

circumference = πd = (3.14)(16) = 50.24 ft

(198°/360°)(50.24) = 27.63 ft

5 0

3 years ago

Helppppppppppoppppppppppppppppppp

NARA [144]

I think the answer would be the last one. a cylinder with radius 4 units.

3 0

3 years ago

SOMEONE PLEASE HELP ME WITH THIS I NEED IT!!!

QveST [7]

Answer:

to be entirely honest i do not know

Step-by-step explanation:

5 0

3 years ago

Emmie has $60 to spend on craft supplies.The tax rate is 8.25%. What is the maximum amount she can spend on craft supplies befor

Margarita [4]

Answer:

$55.05

Step-by-step explanation:

60 x .0825 = 4.95

60 - 4.95 = 55.05

7 0

3 years ago

Plllzzz im new and i neeed help

ella [17]

Answer:

4082

Step-by-step explanation:

Given

The composite object

Required

The volume

The object is a mix of a cone and a hemisphere

Such that:

$r = 10cm$ ---- radius (r = 20/2)

$h = 19cm$

<u>Hemisphere</u>

$r=10cm$

The volume of the cone is:

$V_1 = \frac{1}{3}\pi r^2h$

$V_1 = \frac{1}{3}\pi * 10^2 * 19$

$V_1 = \frac{1900}{3}\pi$

The volume of the hemisphere is:

$V_2 = \frac{2}{3}\pi r^3$

$V_2 = \frac{2}{3}\pi 10^3$

$V_2 = \frac{2000}{3}\pi$

So, the volume of the object is:

$V = V_1 + V_2$

$V = \frac{1900}{3}\pi + \frac{2000}{3}\pi$

$V = \frac{3900}{3}\pi$

$V = 1300\pi$

$V = 1300 * 3.14$

$V = 4082$

8 0

3 years ago