Answer:
it is more intense by 3.0
Step-by-step explanation:
If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
So 7 is greater I am not smart I am just trying to answers some question
0.22% shrinkage as a percent of sales.
To calculate shrinkage you subtract the physical inventory value from the book value.
245,000-237,000 = 800
The shrinkage was $800. To find the shrinkage as a percent of sales take the shrinkage value and divide it by the sales value to get shrinkage as a percentage of sales.
800 / 360,000 = 0.0022....
Multiply Decimal by 100 to get the percentage
100 * 0.0022.... = 0.22%
Answer:
Step-by-step explanation:
t = tutoring and g = grocery store
t + g = 15......t = 15 - g
15t + 9g = 159
15(15 - g) + 9g = 159
225 - 15g + 9g = 159
-15g + 9g = 159 - 225
-6g = - 66
g = -66/-6
g = 11 <===== 11 hrs worked at the grocery store
t + g = 15
t + 11 = 15
t = 15 - 11
t = 4.....4 hrs tutoring
