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3 years ago

Solve the system of linear equations -3x+5=13 and x+4y=-10

Mathematics

2 answers:

andrew-mc [135]3 years ago

7 0

Answer:

(-8/3,-11/6)

Step-by-step explanation:

kari74 [83]3 years ago

6 0

Answer:

(−8/3,−11/6)

Step-by-step explanation:

-3x+5=13 ; x+4y=-10

x=−8/3

and y=−11/6

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A manufacturer inspects 500 personal video players and finds that 296 of them have no defects. the manufacturer sent a shipment

snow_tiger [21]

3351/500 = 6.702
296 times 6.702 is 1983.79
Answer is 1984

7 0

3 years ago

Julie, a police officer, has the following work pattern. She works 3 days, has 4 days off, then works 4 days, then has 3 days of

zalisa [80]

Answer:

See below.

Step-by-step explanation:

For each day number, Y means working, and N means off

Day

1 Y

2 Y

3 Y

4 N

5 N

6 N

7 N

8 Y

9 Y

10 Y

11 Y

12 N

13 N

14 N

15 Y

16 Y

17 Y

18 N

19 N

20 N

21 N

22 Y

23 Y

24 Y

25 Y

26 N

27 N

28 N

29 Y

30 Y

31 Y

32 N

33 N

34 N

35 N

36 Y

37 Y

38 Y

39 Y

40 N

41 N

42 N

43 Y

44 Y

45 Y

46 N

a. Today is day 1. 30 days from today is day 31.

She works on day 31, so she does work 30 days from today.

b. 45 days from today is day 46. She is off on day 46, so she will be off 45 days from today.

8 0

3 years ago

Read 2 more answers

Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with

worty [1.4K]

Answer:

$z$

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu =26$ kilograms and standard deviation $\sigma=4.2$ kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

$X$ "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(26,4.2)$

Where $\mu=26$ and $\sigma=4.2$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

$z=\frac{42.6-26}{4.2}=3.95$

So then the corresponding z scale would be:

$z$

7 0

3 years ago

PLEASE I WILL GIVE BRAINLIEST!

Darya [45]

Answer:

7 + x + 4y

(7 + x) + 4y

x + (7 + 4y)

Step-by-step explanation:

the sum of elements does not change, no matter the order.

4 0

3 years ago

Find sin 2a and cot 2a:

geniusboy [140]

Answer:

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}$

Step-by-step explanation:

$\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\$

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}$

8 0

3 years ago