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3 years ago

A cylinder shaped water tank has a diameter of 8 m and a height of 20 m.

Mathematics

1 answer:

aev [14]3 years ago

7 0

Answer:

602.88 cu ft.

Step-by-step explanation:

V = Bh where B is the area of the base, which is a circle in your problem.

Since the diameter is 8, the radius is 4.

So, B = $\pi r^{2} = 3.14(4^{2} ) = 3.14(16) = 50.24$

V = Bh = 50.24(20) = 1004.8 cu ft = total volume of tank

60% of that volume is .60(1004.8) = 602.88 cu ft.

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Step-by-step explanation:

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2 years ago

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3 years ago

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Check the picture below.

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$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} h=8\\ r=\frac{4.5}{2\pi } \end{cases}\implies V=\pi \left( \cfrac{4.5}{2\pi } \right)^2(8)\implies V=\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \cdot \cfrac{20.25}{\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\underset{\pi }{\begin{matrix} \pi^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }}(\stackrel{2}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}})$

$\bf V=\cfrac{40.5}{\pi }~cm^3~\hspace{9em} \stackrel{\textit{since density is }752kg~per~cm^3}{density\implies 752\left( \cfrac{40.5}{\pi } \right)}\qquad \approx ~~9694$

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