Let the number of dimes = xLet the number of quarters = y You know that each dime is worth $0.10You know that each quarter is worth $0.25 Using the variables above, we can write two equations that represents the total number of coins and total amount. x + y = 47 eq10.10x + 0.25y = 8 eq2 You can use the substitution/elimination method to solve for x and y.<span>3/6/2017 </span>| Michael J.<span>
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Answer:
x = 8
y = 138
Step-by-step explanation:
Answer:
3j + 6
Step-by-step explanation:
5j - (2j - 6) Distribute the negative inside the parentheses
5j - 2j + 6 Combine like terms
3j + 6
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
Answer:
24
Step-by-step explanation:
That's the first number that all your denominators have in common.
