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3 years ago

Given: FGKL is a trapezoid, m∠F=90°, m∠K=120°, FK=LK=a Find: The length of midsegment.

Mathematics

1 answer:

lisov135 [29]3 years ago

7 0

Try this solution (note, the length of midsegment is (KG+FL)/2), all the details are in the attachment.

Answer is marked with green colour.

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9.56 to the nearest hundreth

mariarad [96]

9.56 is the nearest hundredth.
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3 years ago

Part A: Factor 5x2b2 + 14xb2 − 3b2. Show your work.

zavuch27 [327]

Part A:
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Rewriting we have:
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3 years ago

Solve Gx) for the given domain.

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Answer:

The answer and the explanation is in the following pictures. Hope that's helps you.

5 0

3 years ago

20 points! I appreciate it! What is the difference in the areas of the two triangles?

Zanzabum

Answer:

1 ft²

Step-by-step explanation:

Left triangle, area = 10 x 7/2 = 35 ft²

Right triangle, area = 9 x 8/2 = 36 ft²

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6 0

3 years ago

(4-3x)-6<-4 I need help I will give a thanks

Karolina [17]

Answer:

x > $\frac{2}{3}$

Step-by-step explanation:

Change the less than sign to an equals sign so we can solve for x

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Reorder the numbers in the parentheses

(-3x+4)-6 = -4

Get rid of the parentheses and combine like terms

-3x-2 = -4

Add 2 to both sides

-3x = -2

Divide both sides by -3

x = $\frac{2}{3}$

Bkuz you want it to be less than, change the equals sign to a greater than symbol bkuz of the negatives

Hope this helps!

6 0

4 years ago