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Masteriza [31]
3 years ago
9

Suppose​ you're given a data set that classifies each sample unit into one of four​ categories: A,​ B, C, or D. You plan to crea

te a computer database consisting of these​ data, and you decide to code the data as Aequals=​1, Bequals=​2, Cequals=​3, and Dequals=4. Are the data consisting of the classifications​ A, B,​ C, and D qualitiative or​ quantitative? After the data are input as​ 1, 2,​ 3, or​ 4, are they qualitative or​ quantitative?
Mathematics
1 answer:
Sever21 [200]3 years ago
5 0

Answer:

The data A, B, C and D are Qualitative.

The data remains qualitative even when inputed as 1, 2, 3 and 4  

Step-by-step explanation:

The data consisting of A, B, C and D is Qualitative , reason being that they can only be classified into categories.

Also, when the data is inputed as 1, 2, 3 and 4; the data remains Qualitative because theycannotbemeaningfully addd , subtracted, multiplied or divided.

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What is the geometric mean of 12 and 15?
love history [14]

Answer:

The geometric mean is 9.798

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The lifetime of a mechanical assembly in a vibration test is exponentially distributed with a mean of 500 hours. If an assembly
skelet666 [1.2K]

Answer:

A) probability of failure in next 100 hours given that it has been tested for 500 hours without failure is 0.181

B) probability that exactly two have the metabolic defect is 0.03

Step-by-step explanation:

Part A)

Let X be a exponentially random variable with mean = μ = 500 hrs

For exponential distribution:

p.d.f = f(x) = \lambda e^{-\lambda x}\\c.d.f = F(x) = 1 - e^{-\lambda x}\\x\geq 0

                                                         λ = 1/μ

                                                         λ = 0.002

We have to find the  probability of failure in the next 100 hours given that assembly has been tested for 500 hours without a failure.

Using memory less property of exponential distribution:

P(X500) = P (X

using

F(x) = 1 - e^{-\lambda x}\\ \lambda =.002\\x=100\\F(x) = 1- e^{-(.002)(100)}\\F(x) = 1-.8187\\F(x) = 0.181

<h3>Part B)</h3>

Chances of occurrence of metabolic defect = 5%

                                                                 P(C) = .05

No. of randomly selected infants  = n =6

We  have to find the probability that exactly two have the metabolic defect

                                                        ⇒x = 2

Using binomial probability density function:

                                        P = P=\left[\begin{array}{ccc}n\\x\end{array}\right] p^{x} (1-p) ^{n-x}\\\\=\frac{n!}{x!(n-x)!} p^{x} (1-p) ^{n-x}\\=\frac{6!}{2!4!}(.05)^{2}(.95)^{4}\\= 0.03\\

probability that exactly two have the metabolic defect is 0.03

7 0
3 years ago
Help!!!!! What’s the answer
Olegator [25]

D because is the equal to the other side but added allá together

5 0
3 years ago
Brandon knows that there are 16 ounces in 2 cups . what is the ratio of ounces to cups?
Svetlanka [38]
You answer will be 8:1 is 16 ounces hope that helps you.
4 0
3 years ago
Can anyone help me with this problem??
Arlecino [84]

9514 1404 393

Answer:

  (a)  4/3

  (b)  y -3 = 4/3(x -1)

  (c)  y -3 = -3/4(x -1)

  (d)  r = 5

Step-by-step explanation:

a) The slope is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (7 -3)/(4 -1) = 4/3

__

b) The radius is normal to the circle. The point-slope form of the equation for a line can be useful here:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

For slope 4/3, the line through point (1, 3) will have the equation ...

  y -3 = 4/3(x -1) . . . . point-slope equation of the normal

__

c) The tangent is perpendicular to the radius. It will have a slope that is the opposite reciprocal of the slope of the radius: -1/(4/3) = -3/4.

  y -3 = -3/4(x -1) . . . . point-slope equation of the tangent

__

d) The radius can be found from the distance formula.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((4 -1)² +(7 -3)²) = √(3² +4²) = √25 = 5

The radius of the circle is 5.

4 0
3 years ago
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