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3 years ago

the sum of two consecutive odd integers is 64 what is the smaller number plzzzz help also can you some me how to do it

1 answer:

3 0

Divide 64 by 2 which is 32. and since they have to be consecutive odd integers, add one to 32 and subract one from the other 32. 33+31=64

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Anyone Watch's AOT who you fav character

mihalych1998 [28]

Answer:

Levi is fine a_f

Step-by-step explanation:

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2 years ago

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The sum of two numbers is 9 and the sum of their squares is 41. What is the larger number?

Sonbull [250]

The larger number is 5.

<u><em>Explanation</em></u>

Lets assume, the larger number is $a$ and the smaller number is $b$

As the sum of two numbers is 9, so...

$a+b= 9 ...............................(1)$

Now, the sum of their squares is 41, so....

$a^2 + b^2 = 41 .......................................(2)$

First, solving equation (1) for $b$ ....

$b=9-a$

Now, plugging this $b=9-a$ into equation (2) , we will get...

$a^2 +(9-a)^2 = 41\\ \\ a^2 +81-18a+a^2 =41 \\ \\ 2a^2-18a+81 =41 \\ \\ 2a^2-18a+40=0\\ \\ 2(a^2 -9a+20)=0\\ \\ a^2 -9a+20=0\\ \\ (a-5)(a-4)=0\\ \\ a=5,4$

If $a=5 ,$ then $b=9-5=4$

So, the larger number is 5.

5 0

3 years ago

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Plzzzz its due in 15mins1.

BigorU [14]

P = -3
m = -22
p = 4
n = -9

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3 years ago

Find the geometric means in the following sequence. –14, ? , ? , ? , ? , –235,298

timama [110]

The answer should be something like 12, 33, 56, 66, 77

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2 years ago

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V125BC [204]

Answer:

You would pay $2.75

Step-by-step explanation:

a dozen = 12

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2 years ago

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