3 years ago

the sum of two consecutive odd integers is 64 what is the smaller number plzzzz help also can you some me how to do it

1 answer:

3 0

Divide 64 by 2 which is 32. and since they have to be consecutive odd integers, add one to 32 and subract one from the other 32. 33+31=64

You might be interested in

Evaluate the expression m^2 ∙ m^5 ∙ m^-3. Be sure to write your answer in simplest form.

Zielflug [23.3K]

Answer:

m^4

Step-by-step explanation:

To solve you combine all the exponents

5 0

3 years ago

Read 2 more answers

Expand and simplify 4(2x +7) – 3(x + 5)

Tema [17]

Answer:

The answers is 5x + 13

It Equal to 5x + 13

5 0

3 years ago

The explicit formula for an arithmetic sequence is an = 20 + (n − 1)(2). What is the 200th term?

Andrews [41]

Answer:

$a_{200}=418$

Step-by-step explanation:

The explicit formula for an arithmetic sequence is given by :

$a_n=20+(n-1)2$ ...(1)

We need to find the 200th term of the sequence.

Put n = 200 in equation (1)

$a_{200}=20+(200-1)2\\\\=20+199\times 2\\\\=418$

So, the 200th term of the sequence is 418.

7 0

3 years ago

Solve for y in -8×+4y=24

s344n2d4d5 [400]

Factor out the common term 4

-4(2x - y) = 24

Divide both sides by -4

2x-y= - 24/4

Simplify24/4 to 6

2x -y = -6

Subtract 2x from both sides

-y = -6 - 2x

Multiply both sides by -1

y = 6 + 2x

5 0

3 years ago

What is the answer to 1.3 (6.3r - 4.2) = 66.9

liubo4ka [24]

R = 804/91

8.835

this is ur answer i how i helped

5 0

3 years ago

Read 2 more answers