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iVinArrow [24]
3 years ago
8

Are x^2 and x like terms?

Mathematics
2 answers:
Anton [14]3 years ago
8 0

Hi!

No they are not because x^2 has 2 as the exponent and x has 1 as the exponent. you can add them together

Hope this helps!

Igoryamba3 years ago
5 0

X^2 and X are not like terms. They have different degrees.

For example, 2x^2 and x^2 are like terms because they have the same degrees. When you add them you get 3x^2. If you try to add x^2 and x, you cant do it because they have different degrees.

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What is AD to nearest tenth?
Lynna [10]
AD = √(19^2 + 3^2)
AD = √370
AD = 19.2

answer
C. 19.2
5 0
3 years ago
DETAILS
Nina [5.8K]

The perimeter of the rectangle as a function of w only is P(w) = 2[√(324 - w²) + w]

The perimeter of the rectangle P = 2(h + w)

Since the diagonal is D = 18 feet, using Pythagoras' theorem, we have that

D² = h² + w²

So, making h subject of the formula, we have

h = √(D² - w²)

h = √(18² - w²)

h = √(324 - w²)

Since the perimeter of the rectangle P = 2(h + w), substituting the value of h into P, we have

P = 2(h + w)

P = 2[√(324 - w²) + w]

P(w) = 2[√(324 - w²) + w]

So, the perimeter of the rectangle as a function of w only is P(w) = 2[√(324 - w²) + w]

The angle θ as a function of w only is θ(w) = sin⁻¹[w/18]

Using trigonometric functions, sinθ = w/D

since D = 18, substituting the value of D into the equation, we have

sinθ = w/18

Taking inverse tan of both sides, we have

θ = sin⁻¹[w/18]

θ(w) = sin⁻¹[w/18]

So, the angle θ as a function of w only is θ(w) = sin⁻¹[w/18]

Learn more about perimeter of a rectangle here:

brainly.com/question/7538991

4 0
3 years ago
What is the distance between (0,-1), (5,1)​
BlackZzzverrR [31]

Answer:

square root of 29 or approximately 5.38

7 0
3 years ago
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2 years ago
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Obtain the required confidence interval for the difference between two population proportions. Assume that independent simple ra
Thepotemich [5.8K]

Answer:

The 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

Step-by-step explanation:

The formula for confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

From the question

We have two groups.

Group 1 = For women

A survey found that 37 of 74 randomly selected women

p1 = x/n1

n1 = 74

x1 = 37

p1 = 37/74

p1 = 0.5

Group 2 = For Men

A survey found out that 47 of 74 randomly selected men follow a regular exercise program

p2 = x/n1

n2= 74

x2 = 47

p2 = 47/74

p2 = 0.6351351351 ≈ 0.635

z = z score for 95% Confidence Interval = 1.96

The confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

0.5 - 0.635 ± 1.96 × √0.5 (1 - 0.5)/74 + 0.635(1 - 0.635)/74

-0.135 ± 1.96 × √(0.5 × 0.5)/74 + (0.635× 0.365)/74

-0.135 ± 1.96 × 0.08068750209663572

-0.135 ± 0.158147504109406

Hence:

= -0.135 - 0.158147504109406

= -0.2931475041

Approximately = -0.293

= -0.135 + 0.158147504109406

= 0.0231475041

Approximately = 0.023

Therefore, the 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

6 0
2 years ago
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