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3 years ago

9

If you draw three cards from a regular deck of 52 cards, keeping each card out of the deck after you draw it, what are the chanc

es you draw a seven and two queens?

1 answer:

Alex787 [66]3 years ago

8 0

The chances of drawing a seven and two queens are 0.036199095% or <span>2/5525. YOU'RE WELCOME :) ??</span>

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Evaluate the following expression using the values given: (1 point)

garik1379 [7]

3(3)^2 - (-2)^3 - (-2)^3 + 5
27 - (-8) - (-8) +5
35 - (-8) + 5
43 + 5
48

4 0

3 years ago

Solve for B -18r+18s=-4

hodyreva [135]

Answer:

B=-4+18r-18s

Step-by-step explanation:

move all terms not containing B to the right side of the equation. Hope this helps.

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2 years ago

Help me with this please

Tcecarenko [31]

Answer:

It would be -13

Step-by-step explanation:

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2 years ago

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A company has an opportunity to bid on three contracts. Determine which would be the best investment given the information in th

MariettaO [177]

CONTRACT PROFIT, (P)* OF PROFIT...(P)*. TO BREAK EVEN...LOSS, (P)* OF LOSS

Southeast $45,000, 50% 30% $6,000, 20%

Southwest $60,000, 35% 40% $10,000, 25%

California $112,000, 20% 40% $40,000, 40%

I think that the best contract would be with SOUTHEAST. It probability of having a profit is higher than the other two at 50% while its probability of incurring a loss is lesser than the other two at 20%.

Despite the bigger value of its contract profit of the other two, these value will still be greatly affected by its corresponding probabilities.

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2 years ago

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The nursing department of a college surveyed two hundred graduates from their programs about their current

mel-nik [20]

Answer: The required probability is 0.008.

Step-by-step explanation:

Since we have given that

Probability of bachelor's degree = 0.45

Probability of working in nursing = 0.85

Probability of both = 0.4

So, Probability of getting a graduate is currently working in nursing, given that they earned a bachelor's degree would be :

$P(N|B)=\dfrac{P(N\cap B)}{P(B)}\\\\P(N|B)=\dfrac{0.4}{0.45}\\\\P(N|B)=0.008$

Hence, the required probability is 0.008.

3 0

3 years ago