Hidden right triangle
28 feet tall (1 leg)
the piece that fell over is the hypotonuse
last leg is what we need to find
81-28=53
a²+b²=c²
a and b are legs and c is the hypotonuse
given
on leg is 28 and the hypotonuse is 53
th othe leg is b
28²+b²=53²
784+b²=2809
minus 784 from both sides
b²=2025
sqrt both sides
b=45
answer is 45ft
Answer:
a−4b
Step-by-step explanation:
Combine Like Terms:
=4a+−6b+−3a+2b
=(4a+−3a)+(−6b+2b)
=a+−4b
have a great day
In order to find height (h), tan20 = h/26
Now for the left part of base (b1), where b2 = 26 and entire base (b) = b1+b2
So b = 13.03+26 = 39.03
Now Area (A) = 1/2bh = 1/2 (39.03)(9.46)
A = 184.59
Answer:
width = 12 ft
Step-by-step explanation:
Given the figure of the pond and the fact that the corners form a right triangle that is across from the string of flags, you can use the Pythagorean Theorem to solve for the width of the triangle that is formed by the flags:
a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the diagonal or hypotenuse. Using 16 for 'a' and 20 for 'c':
16² + b² = 20²
256 + b² = 400
Subtract 256 from both sides: 256 - 256 + b² = 400 - 256 or b² = 144
Take the square root of both sides: √b² = √144 or b = 12 ft
