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Angelina_Jolie [31]
3 years ago
6

a rectangular ponds refectuons in a part is 16 feet long. The maintenance crew placed a string of flags 20 feet long across the

pond diagonally as shown below. What is the width of the pond​

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Answer:

width = 12 ft

Step-by-step explanation:

Given the figure of the pond and the fact that the corners form a right triangle that is across from the string of flags, you can use the Pythagorean Theorem to solve for the width of the triangle that is formed by the flags:

a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the diagonal or hypotenuse.  Using 16 for 'a' and 20 for 'c':

16² + b² = 20²

256 + b² = 400

Subtract 256 from both sides: 256 - 256 + b² = 400 - 256 or b² = 144

Take the square root of both sides:  √b² = √144  or b = 12 ft

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<u>Answer:</u>

A building makes a 90^{\circ} angle with the ground .The two interior angles are 70^{\circ} and 20^{\circ}

<u>Solution: </u>

Given, a ladder which is against the building wall makes an exterior angle of 110^{\circ}

And building makes a  90^{\circ} angle with the ground.

So, altogether it makes a right angle triangle with ladder as hypotenuse and ground as base leg and building as another leg.  

Now, we know that, sum of exterior angles and interior angles equals to 180^{\circ}

Here, in the case of ground and ladder, exterior angle is 110^{\circ} and interior angle is unknown.

Exterior angle + interior angle = 180

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We have found one of the two interior angles of right angle triangle.

We know that, sum of angles in a triangle is 180 degree

Known Interior angle + unknown interior angle + right angle = 180

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Unknown interior angle + 160 = 180

Unknown interior angle = 180 - 160

Unknown interior angle = 20^{\circ}

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Step-by-step explanation:

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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
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Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

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or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

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3 years ago
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