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borishaifa [10]
4 years ago
11

Use the function below:

Mathematics
1 answer:
andrew-mc [135]4 years ago
4 0
The given data is
x:  0     π/2    π    (3π)/2   2π
y:  2     0       2    4           2

The function that models the data is (see the graph shoen below)
y=2cos(x+ \frac{ \pi }{2})+2

The amplitude is 2.
The midline is y = 2
The phase is -π/2.
The period is 2π.

Answer:
Amplitude: 2; Midline: y = 2


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2k - 2j when j=4&k=6 replace the variable with the given amount and solve the problem​
eimsori [14]

Answer:

4

Step-by-step explanation:

first, plug in 6 for k.<em> (</em><em>i</em><em>t</em><em> </em><em>doesn't</em><em> </em><em>matter</em><em> </em><em>which</em><em> </em><em>value</em><em> </em><em>you</em><em> </em><em>plug</em><em> </em><em>in</em><em> </em><em>first</em><em>;</em><em> </em><em>you can start with j </em><em>o</em><em>r</em><em> </em><em>k</em><em>,</em><em> </em><em>but i'm just </em><em>s</em><em>t</em><em>a</em><em>r</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>with</em><em> </em><em>k</em><em> </em><em>since</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>v</em><em>a</em><em>r</em><em>i</em><em>a</em><em>b</em><em>l</em><em>e</em><em> </em><em>that</em><em> </em><em>comes</em><em> </em><em>first</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>expression</em><em>)</em>

2k - 2j => 2(6) - 2j

then plug in 4 for j.

2(6) - 2j => 2(6) - 2(4)

now your expression is 2(6) - 2(4). simplify by multiplying 2(6) and then -2(4) <em>(</em><em>again</em><em>,</em><em> </em><em>it</em><em> </em><em>doesn't</em><em> </em><em>matter</em><em> </em><em>which</em><em> </em><em>one</em><em> </em><em>you</em><em> </em><em>multiply</em><em> </em><em>first</em><em>,</em><em> </em><em>as</em><em> </em><em>long</em><em> </em><em>as</em><em> </em><em>you</em><em> </em><em>make</em><em> </em><em>sure</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>minus</em><em> </em><em>sign</em><em> </em><em>between</em><em> </em><em>2</em><em>(</em><em>6</em><em>)</em><em> </em><em>and</em><em> </em><em>2</em><em>(</em><em>4</em><em>)</em><em> </em><em>gets</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>2</em><em> </em><em>in</em><em> </em><em>2</em><em>(</em><em>4</em><em>)</em><em>.</em><em>)</em>

2(6) - 2(4) => 12 - 2(4)

12 - 2(4) => 12 - 8

subtract 8 from 12.

12 - 8 = 4

your answer is 4, therefore when j = 4 and k = 6, 2k - 2j = 4.

i hope this helps! have a nice day <3

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