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3 years ago

The U.S. government pays for _____ that producers would most likely not provide in the marketplace, such as building roads.

Business

2 answers:

Bas_tet [7]3 years ago

8 0

The answer is B hope this helps.

katrin [286]3 years ago

5 0

The answer is: public goods and services

Public goods and services refers to a collection of services and infrastructures that can be used by citizens of a certain country. These services and infrastructures is being paid from the tax income that taken by the government annually.

Other examples of public goods and services are public library, public part, welfare programs, etc.

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The more precisely defined the target market is, the _____ the numbers are to estimate.

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The answer is a I believe I'm not really sure

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Hobson Company bought the securities listed below during 2020. These securities were classified as trading securities. In its De

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$50,800

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$1500 at 12% interest for two years

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In order to package one of their products, Acme Box Co. needs to construct a box whose bottom side has length 3 times its width.

Len [333]

Answer:

(a)Total Cost, C=20LW+12LH+12WH

(b) $C(W)=\dfrac{60W^3+800}{W}$

(c)W=1.88ft, L=5.64 ft and H=4.72 ft.

$Minimum \:cost, C\approx \$638 $ (to the nearest dollar)$$

Explanation:

Given the dimensions of the box to be L,W and H.

(a)

The material for the top and bottom of the box cost $10 per square foot
The material used to build the four sides of the box cost $6 per square foot.
Area of Top and Bottom=2LW

Cost of Top and bottom=$10 X 2LW=20LW
Area of four Sides =2(LH+WH)
Cost of Four Sides =$6*2(LH+WH)=12(LH+WH)
Total Cost, C=20LW+12LH+12WH

(b)The bottom side has length 3 times its width.

L=3W

Volume of the box=50 cubic feet.

$Volume,V=LWH=3W^2H$

$3W^2H=50\\H=\dfrac{50}{3W^2}$

Substituting L=3W and $H=\dfrac{50}{3W^2}$ into the cost function C.

C=20LW+12LH+12WH

$C=20LW+12LH+12WH\\=20*3W*W+12*3W*\dfrac{50}{3W^2}+12W*\dfrac{50}{3W^2}\\=60W^2+\dfrac{600}{W}+\dfrac{200}{W}\\=\dfrac{60W^3+600+200}{W}\\C(W)=\dfrac{60W^3+800}{W}$

(c)The minimum cost occurs at the point where the derivative of the cost function equals zero.

$If\:C(W)=\dfrac{60W^3+800}{W}\\C'(W)=\dfrac{120W^3-800}{W^2}=0\\120W^3-800=0\\120W^3=800\\W^3=\frac{800}{120}\\ W=1.88$

Recall:

$L=3W=5.64 feet\\H=\dfrac{50}{3W^2}=\dfrac{50}{3(1.88)^2}=4.72 ft$

The dimensions of the box that minimize the cost are W=1.88ft, L=5.64 ft and H=4.72 ft.

Cost of the box at these dimension

$C(W)=\dfrac{60W^3+800}{W}\\C(1.88)=\dfrac{60(1.88)^3+800}{1.88}\approx \$638 $ (to the nearest dollar)$$

7 0

3 years ago