A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².
Answer:
X= 50°
Y= 70°
Z= 30°
BDE= 30°
2BDE= 60°
Step-by-step explanation:
(2x -70 )+z+(2x+20)=180...(sum of angle on a straight line)
2x -70 = BDE... alternate angles
Y + (2x-70)+(50+x-20) = 180...(sum of angles in a triangle)
X-20 = z ... alternate and opposite angles
(2x -70 )+z+(2x-+20)=180
2x-70 + x-20 +2x +20= 180
5x -70= 180
5x = 250
X= 50°
X-20 = z
50-20= z
30° = z
2x -70 = BDE
2(50) -70 = BDE
100-70 = BDE
30°= BDE
Y + (2x-70)+(50+x-20)
Y + 100-70 +50 +50 -20 = 180
Y + 200-90=180
Y= 70°
2BDE = 2*30
2BDE= 60°
The area of any circle is (pi) · (radius)² .
The radius is 1/2 of the diameter.
For your circle, the radius is 1/2 of 14 inches = 7 inches,
and the area is
(pi) · (7 inches)²
= (pi) · (49 square inches)
= 153.9 square inches (rounded)
2y to the second power= 4y
-6y to the second power= -36y
Answer:
i think its D
sry if im wrong
step-by-step explanation:
