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Zarrin [17]
3 years ago
7

What type of triangle do i have if the angles are:15, 10,155

Mathematics
1 answer:
xenn [34]3 years ago
6 0
Obtuse, accute, obtuse, acute, A.
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adell [148]
<span>l 18+7 l / 10 - l -16+26 l /6 
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= 5/2 - 5/3
= 15/6 - 10/6
= 5/6

answer </span><span>5/6 (3rd choice)</span>
8 0
3 years ago
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Quanto é 9+(-4-2)= ?
lana [24]

Answer:

9+(-4-2)

=9+(-6)

=9-6

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6 0
3 years ago
All I need to know is the answer to number one.
zysi [14]
If the number is negative than it is less than it's absolute value.
4 0
3 years ago
You make $7 an hour. You work 40 hours a week for a year. (52 weeks) How much will you make?
valina [46]

If you made $7 an hour and worked for 40 hours, every day for a year, you would make $14,560 a year and about $1,213.33 a month.

Because 7 x 40 = 280 (which is how much money you make a week.)

And 280 x 52 = 14,560 (because you would work for 52 weeks).

I hope this helped! Good luck and have a great night!

8 0
3 years ago
According to industry sources, online banking is expected to take off in the near future. The projected number of households (in
Airida [17]

Answer:

(a) The least-square regression line is: y=4.662+2.709x.

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

y=\alpha +\beta x

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

(a)

The formula to compute intercept and slope is:

\begin{aligned}        \alpha  &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}  \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        \end{aligned}

The values of ∑<em>X</em>, ∑<em>Y</em>, ∑<em>XY</em> and ∑<em>X</em>² are computed in the table below.

Compute the value of intercept and slope as follows:

\begin{aligned}        \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}

The least-square regression line is:

y=4.662+2.709x

(b)

For the year 2007 the value of <em>x</em> is 10.

Compute the value of <em>y</em> for <em>x</em> = 10 as follows:

y=4.662+2.709x

  =4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0
2 years ago
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