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3 years ago

Let u be an angle in the 4th quadrant with cos u=8/9 Then sin u=

1 answer:

5 0

To solve for the last side of the triangle, use the Pythagorean Theorem:
(8)^2 + x^2 = (9)^2
x = sqrt of 17
However, this is a NEGATIVE sqrt 17 because the terminal side is in quadrant 4, meaning that this side is under the X-axis and therefore negative.
Now that you know the side opposite of u in the triangle, do opposite/hypotenuse.
sin u = -(sqrt 17)/9

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Are the two expressions equivalent 5(3x+8) 8x+8 when x=10

Brums [2.3K]

Answer:no

Step-by-step explanation:

5(3(10)+8)

5(30+8)

5(38)=190

8(10)+8

80+8

88≠190 so no

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3 years ago

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saw5 [17]

30 Dollars.

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3 years ago

Which of the following xpressions is equivalent to -1/4 - 5/3? -1/4 + (-5/3) or - 1/4 + 5/3?

Nadusha1986 [10]

-1/4 + (-5/3)

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3 years ago

The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.

Mashcka [7]

Answer:

$\frac{\sqrt{10}}{2}$

Step-by-step explanation:

The diagonal forms two 45-45-90 triangles, with the diagonal being the hypotenuse of both. The Pythagorean Theorem states that $a^2+b^2=c^2$ , where $c$ is the hypotenuse of the triangle, and $a$ and $b$ are the two legs of the triangle.

From the Isosceles Base Theorem, the two legs of a 45-45-90 triangle are always equal. Since we're given a diagonal of $\sqrt{5}$ , we have:

$x^2+x^2=\sqrt{5}^2,\\2x^2=5,\\x^2=\frac{5}{2},\\x=\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{5}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\boxed{\frac{\sqrt{10}}{2}}$

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3 years ago

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torisob [31]

I’m pretty sure it’s a candle but I’m not 100% sorry if I’m wrong!!!

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2 years ago