Area of cone=3.14*9+3*6*3.14=27*3.14
=84.78 cm^2 if we cut into four identical pieces we get two triangle surfaces also for 1 piece and and 1/4 of the original surface area =21.195+15.588=36.783squarecm
Answer:
B
Step-by-step explanation:We know Volume = (a*b*c)
Answer:
Angle 1 = 75°
Angle 2 = 55°
Angle 3 = 55°
Angle 4 = 40°
Angle 5 = 140°
Angle 6 = 40°
Angle 7 = 75°
Angle 8 = 65°
Angle 9 = 115°
Step-by-step explanation:
1) We start with angle 2
Angle 2
Angles on a straight line = 180°
Hence,
b + 125° = 180°
b = 180° - 125°
b = 55°
Angle 2 = 55°
2)Angle 1
The sum of angles in a triangle = 180°
Hence
Let Angle 1 = a
50° + 55° + a = 180°
a = 180° - (50° + 55°)
a = 180° - 105°
a = 75°
3)Angle 3
Angle 2 and Angle 3 are vertical angles
So we use the Vertical angle theorem
This means
Angle 2 = Angle 3
Angle 2 = 55°
Hence, Angle 3 = 55°
4) Angle 4
Sum of Angles in a triangle = 180°
Let Angle 4 = d
Hence:
85° + Angle 3 + d = 180°
85° + 55° + d = 180°
d= 180° - (85° + 55°)
d = 180°- 140°
d = 40°
5)Angle 5
Angle 4 and Angle 5 are angles on a straight line
Sum of angles on a straight line = 180°
Angle 4 = 40°
Let Angle 5 = e
Hence:
40° + e = 180°
Collect like terms
e = 180° - 40°
e = 140°
6) Angle 6
Angle 4 and Angle 6 are vertical angles
Using Vertical angle theorem,
Angle 4 = Angle 6
Angle 4 = 40°
Hence, Angle 6 = 40°
7)Angle 9
Solving for Angle 9,
Sum of angles on a straight line = 180°
Angle 9 = i
i + 65° = 180°
i = 180° - 65°
i = 115°
8) Angle 8
= Angle 9 and Angle 8 are angles in a straight line
= Angle 8 = h
h + 115° = 180°
h = 180° - 115°
h = 65°
9)Angle 7
Sum of angles in a triangle = 180°
Angle 7 = g
g = 180° - (65° + Angle 6)
= 180° - (65 + 40
= 180° - 105°
= 75°
The y-value of the vertex is positive 3, as shown by the +3 on the right hand side of the equation, and the x-value is -1, from the (x+1)^2 (remember, when the number is inside the brackets, flip the sign) The vertex would be (-1, 3)
If you are looking for a rigorous answer (calculus), we must find the mininum point of the equation: f(x) = (x+1)^2 + 3 f
f'(x) = 2(x+1) = 2x + 2
2x + 2 = 0
x = -1
f(1) = (-1 + 1)^2 + 3
f(1) = 0 + 3 = 3
(-1, 3)
