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3 years ago

Calculate the pay for the following day of a

Mathematics

1 answer:

Juliette [100K]3 years ago

4 0

Answer:

$74.25

Step-by-step explanation:

Morning shift is 4 hours long and pay is 11 dollars per hour:

4*11= 44

Afternoon shift is 2 hour 45 min long 11 dollars per hour:

2.75*11= 30.25

Add both:

44+30.25=$74.25

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What's the answer to: divide £48 in the ratio 7:5 (please show your working, much appreciated)

Brums [2.3K]

I can see you come from outside the USA. No insults intended!!
.
Anyways, we have to put one side of the ratio and match it to 48.
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Or even better...
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MAKE!!
A!!
PROPORTION!!
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So... Let's say 7 is proportional to 48... so 7/5 = 48/x, where x is the number equivalent to ratio of 5.
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Cross multiply!!
<span>.
</span>7x = 240.
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Divide 7 on both sides.
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x = 34 2/7.
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Hope I helped!!

4 0

2 years ago

How to find the perimeter of a diagram

Dimas [21]

To find the perimeter of a rectangle, add the lengths of the rectangle's four sides. If you have only the width and the height, then you can easily find all four sides (two sides are each equal to the height and the other two sides are equal to the width). Multiply both the height and width by two and add the results.

7 0

2 years ago

If each interior angle of a regular polygon measures 120 , how many sides does the polygon have?

KatRina [158]

Answer:

the ans is 6 sides i guess

3 0

2 years ago

Read 2 more answers

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

In a recent? year, person A and person B had two concert? tours, and together they generated $ 192.9 million in ticket sales. If

Nuetrik [128]

Answer: Person A generates 107.6 millions and person B generates 85.3 millions.

Step-by-step explanation:

Let 'x' millions be the amount generated by person A then the amount generated by person B be 'x-22.3' millions.

Since they both earn together $192.9 millions.

So according to the our assumptions we have,

$x+x-22.3=192.9\\\Rightarrow\ 2x=192.9+22.3\\\Rightarrow\ 2x=215.2\\\Rightarrow\ x=107.6$

Therefore, the amount generated by person A=107.6 millions

And the amount generated by person B= 192.9 millions - 107.6 millions

=85.3 millions

6 0

2 years ago