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3 years ago

6

A total of 516 tickets were sold for the school day. There were either adult tickets or student tickets. The number of student t

ickets sold was three times the number of adult tickets were sold?

2 answers:

prisoha [69]3 years ago

6 0

Answer:

Step-by-step explanation:

s=3a

t=s+a

t=516

now lets use 3a instead of s.

516=3a+a

516=4a

a=129 (adult)

s=3(129)

s=387 (student)

saveliy_v [14]3 years ago

3 0

Same answer as the one above !

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grigory [225]

The system of inequalities are x + y ≥ 7 and 3.75x + 1y ≤ 20 The one possible solution is 4 cupcakes and 3 donuts.

<u>Solution:</u>

Given, Daniel and his children went into a bakery and where they sell cupcakes for $3.75 each and donuts for $1 each.

Daniel has $20 to spend and must buy a minimum of 7 cupcakes and donuts altogether.

⇒ "x" represents the number of cupcakes purchased

⇒ "y" represents the number of donuts purchased,

we have to write and solve a system of inequalities graphically and determine one possible solution.

Now, he should buy minimum 7 items, then x + y ≥ 7 ⇒ (1)

And, he has $20, so his maximum purchase is $20 then, 3.75x + 1y ≤ 20 ⇒ (2)

Now, suppose that he took 5 cupcakes, then he must take at least 2 donuts to satisfy (1)

So, substitute x and y values in (2)

⇒ 3.75(5) + 1(2) ≤ 20

⇒ 20.75 ≤ 20 ⇒ condition failed

So he can take maximum of 4 cupcakes only, and subsequently he has to take minimum of 3 donuts.

Hence, the one possible solution is 4 cupcakes and 3 donuts

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What is the quotient when (10n^2 - 37n - 12) is divided by (n - 4)

dangina [55]

Using polynomial long division:

(10n^2 - 37n - 12) divided by (n - 4) is

10n+3,

<h2><u><em>which is number four</em></u></h2>

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2 years ago

If frequency of being late is .15 how often late in 100

koban [17]

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3 years ago

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Hi there!

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3 years ago

A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?

DENIUS [597]

The answer is 15 in³.

The volume of the cone is:
$V_1= \pi r_1 ^{2} \frac{h_1}{3} = \frac{ \pi r_1^{2} h_1}{3}$
where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone

The volume of the cylinder is:
$V_2= \pi r_2h_2^{2}$
where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone

Since <span>the cone fits exactly inside of the cylinder, they have the same radius and the height:
r</span>₁ = r₂
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Also:
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Now, let's write two volume formulas together:
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We can include V₂ into V₁:
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